摘要:1.如图2-82所示.在△ABC中.AD是∠BAC的外角∠CAE的平分线.求证:AB∶AC=BD∶DC.
网址:http://m.1010jiajiao.com/timu3_id_775668[举报]
如图所示,在△AOB中,∠B=30°, 将△AOB绕点O顺时针旋转52°得到△A′OB′,边A′B′与边OB交于点C(A′不在OB上),则∠A′CO的度数为
[ ]
A.22°
B.52°
C.60°
D.82°
查看习题详情和答案>>
B.52°
C.60°
D.82°