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设A=x3-2x2+4x+3,B=x2+2x-6,C=x3+2x-3,求A-(B+C)的值,其中x=-2.
已知A=x3-5x2,B=x2-11x+6,求:(1)A+2B;(2)当x=1时,求A+5B的值.
已知2x-y=0,求分式的值?[提示:x3-y3=(x-y)(x2+xy+y2)]
已知x3·xa·x2a+1=x31,求a的值.