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(y-2)(y2-6y-9)-y(y2-2y-15),其中y=-2.
先化简,再求值:
(1)(3x+1)(2x-3)-(6x-5)(x-4),其中x=2;
(2)(y-2)(y2-6y-9)-y(y2-2y-15),其中y=1.