摘要:如图所示, 直线AB.CD相交于O, OE平分∠AOD, ∠FOC=900, ∠1=400, 求∠2和∠3的度数. 解: ∠1=400, ∠BOD=900-400=500 ∠AOD=1800-500=1300, ∠AOC与∠AOD互补, ∴∠3=500, ∠2=∠AOD=650
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