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(-)2002×(1)2003=________.
(1)-32-(-2)2;
(2);
(3)(-10)2+[(-4)2-(3+32)×2];
(4);
(5);
(6)(-2)3-3×[(-4)2+2]-(-3)2÷(-2);
(7)(-2)2003+(-2)2002;
(8)(-0.25)2009×42004.
2003-[2003-(2002-2003)]的值等于
[ ]
( )2002×(1.5)2003÷(-1)2004=________.
12 × (-3)2-(-)2003×(-2)2002÷