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已知函数f(x)=ax2+bcosx+sinx-1满足f()=5,则f(-)的值是
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设f(x)=asin(πx+α)+bcos(πx+β),其中a,b,α,β∈R,且ab≠0,α≠kπ(k∈Z).若f(2009)=5,则f(2010)等于( )
A.4 B.3 C.-5 D.5
已知f(x)=x7+ax5+bx-5,且f(-3)=5,则f(3)=( )
A.-15 B.15 C.10 D.-10