摘要:20. 已知正三角形的三个顶点都在抛物线上.其中为坐标原点.设圆是的内接圆(点为圆心) (I)求圆的方程, (II)设圆的方程为.过圆上任意一点分别作圆的两条切线.切点为.求的最大值和最小值. 本小题主要考查平面向量.圆与抛物线的方程及几何性质等基本知识.考查综合运用解析几何知识解决问题的能力.满分14分. (I)解法一:设两点坐标分别为..由题设知 . 解得. 所以.或.. 设圆心的坐标为.则.所以圆的方程为 .····································································································· 4分 解法二:设两点坐标分别为..由题设知 . 又因为..可得.即 . 由..可知.故两点关于轴对称.所以圆心在轴上. 设点的坐标为.则点坐标为.于是有.解得.所以圆的方程为.····································································································· 4分 (II)解:设.则 .········································ 8分 在中..由圆的几何性质得 .. 所以.由此可得 . 则的最大值为.最小值为. 江西理

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