如图甲所示,质量m=2kg的物体在水平面上向右做直线运动.过a点时给物体作用一个水平向左的恒力F并开始计时,选水平向右为速度的正方向,通过速度传感器测出物体的瞬时速度,所得v﹣t图象如图乙所示.取重力加速度为g=10m/s2.求:                                                                                                                                 

(1)物体在0﹣4s内和4﹣10s内的加速度的大小和方向                                           

(2)力F的大小和物体与水平面间的动摩擦因数μ                                                   

(3)10s末物体离a点的距离                                                                                    

(4)10s后撤去拉力F,求物体再过15s离a点的距离                                               

                        

                                                                                                                                 


在探究物体的加速度a与物体所受外力F、物体质量M间的关系时,采用如图所示的实验装置,小车及车中的砝码质量用M表示,盘及盘中的砝码质量用m表示.                                                                     

                                                     

(1)当M与m的大小关系满足                                                           时,才可以认为绳子对小车的拉力大小等于盘和砝码的重力.                                                                                                        

(2)某一组同学先保持盘及盘中的砝码质量m一定来做实验,其具体操作步骤如下,以下做法正确的是        .          

A.平衡摩擦力时,应将盘及盘中的砝码用细绳通过定滑轮系在小车上                         

B.每次改变小车的质量时,不需要重新平衡摩擦力                                                  

C.实验时,先放开小车,再接通打点计时器的电源                                                  

D.用天平测出m以及小车质量M,小车运动的加速度可直接用公式求出                  

(3)另两组同学保持小车及车中的砝码质量M一定,探                  究加速度a与所受外力F的关系,由于他们操作不当,这两组同学得到的a﹣F关系图象分别如图1和图2所示,其原因分别是:                

图1:                                                                                                                     

图2:                                                                                                                     

                                                                                                                                 


(1)图1游标卡尺读数为                                                                               mm.    

(2)某兴趣小组的同学利用如图2所示的实验装置,测量木块与长木板之间的动摩擦因数,图中长木板水平固定.                                                                                                                                    

①实验过程中,打点计时器应接在交流电源上,调整定滑轮的高度,使绳子拉力方向跟平板平行.                        

②已知重力加速度为g,测得木块的质量为M,                                                         

砝码盘和砝码的总质量为m,砝码盘、砝码和木块                                                    

的加速度大小为a,则木块与长木板之间的动摩擦                                                      

因数μ=                                                                                                           .       

③实验时,某同学得到一条纸带,如图3所示,每隔三个计时点取一个计数点,记为图中0、1、2、3、4、5、6点.测得相邻两个计数点间的距离分别为s1=0.96cm,s2=2.88cm,s3=4.80cm,s4=6.72cm,s5=8.64cm,s6=10.56cm,打点计时器的电源频率为50Hz.计算此纸带的加速度大小a=                                                   m/s2,打计数点“4”时纸带的速度大小v=                                         m/s.(保留两位有效数字)

                          

                                                                                                                                 

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