ÌâÄ¿ÄÚÈÝ

5£®ÒªÊ¹Õæ¿ÕÖеÄÁ½¸öµãµçºÉ¼äµÄ¿âÂØÁ¦Ôö´óµ½Ô­À´µÄ4±¶£¬ÏÂÁз½·¨ÖпÉÐеÄÊÇ£¨¡¡¡¡£©
A£®Ã¿¸öµãµçºÉµÄ´øµçÁ¿ºÍÁ½¸öµãµçºÉ¼äµÄ¾àÀë¶¼Ôö´óµ½Ô­À´µÄ2±¶
B£®±£³ÖµãµçºÉµÄ´øµçÁ¿²»±ä£¬Ê¹Á½¸öµçºÉ¼äµÄ¾àÀëÔö´óµ½Ô­À´µÄ2 ±¶
C£®Ê¹Ò»¸öµãµçºÉµÄµçºÉÁ¿¼Ó±¶£¬ÁíÒ»¸öµãµçºÉµÄµçºÉÁ¿±£³Ö²»±ä£¬Í¬Ê±½«Á½¸öµãµçºÉ¼äµÄ¾àÀë¼õСΪԭÀ´µÄ$\frac{1}{2}$
D£®±£³ÖµãµçºÉµÄµçºÉÁ¿²»±ä£¬½«Á½¸öµãµçºÉµÄ¾àÀë¼õСµ½Ô­À´µÄ$\frac{1}{2}$

·ÖÎö ÅжÏÁ½¸öµãµçºÉ¼äµÄ¿âÂØÁ¦£¬¸ù¾Ý¿âÂØ¶¨Âɹ«Ê½F=k$\frac{Qq}{{r}^{2}}$ ·ÖÎö¼´¿É£®

½â´ð ½â£ºA¡¢Ã¿¸öµãµçºÉµÄ´øµçÁ¿ºÍÁ½¸öµãµçºÉ¼äµÄ¾àÀë¶¼Ôö´óµ½Ô­À´µÄ2±¶£¬¸ù¾Ý¿âÂØ¶¨Âɹ«Ê½F=k$\frac{Qq}{{r}^{2}}$£¬¿âÂØÁ¦´óС²»±ä£¬¹ÊA´íÎó£»
B¡¢±£³ÖµãµçºÉµÄ´øµçÁ¿²»±ä£¬Ê¹Á½¸öµçºÉ¼äµÄ¾àÀëÔö´óµ½Ô­À´µÄ2±¶£¬¸ù¾Ý¿âÂØ¶¨Âɹ«Ê½F=k$\frac{Qq}{{r}^{2}}$£¬¿âÂØÁ¦¼õСΪ$\frac{1}{4}$±¶£¬¹ÊB´íÎó£»
C¡¢Ê¹Ò»¸öµãµçºÉµÄµçºÉÁ¿¼Ó±¶£¬ÁíÒ»¸öµãµçºÉµÄµçºÉÁ¿±£³Ö²»±ä£¬Í¬Ê±½«Á½¸öµãµçºÉ¼äµÄ¾àÀë¼õСΪԭÀ´µÄ$\frac{1}{2}$£¬¸ù¾Ý¿âÂØ¶¨Âɹ«Ê½F=k$\frac{Qq}{{r}^{2}}$£¬¿âÂØÁ¦Ôö¼ÓΪ8±¶£¬¹ÊC´íÎó£»
D¡¢±£³ÖµãµçºÉµÄµçºÉÁ¿²»±ä£¬½«Á½¸öµãµçºÉµÄ¾àÀë¼õСµ½Ô­À´µÄ$\frac{1}{2}$£¬¸ù¾Ý¿âÂØ¶¨Âɹ«Ê½F=k$\frac{Qq}{{r}^{2}}$£¬¿âÂØÁ¦Ôö¼ÓΪ4±¶£¬¹ÊDÕýÈ·£»
¹ÊÑ¡£ºD£®

µãÆÀ ±¾ÌâÊÇ¿âÂØ¶¨ÂɵÄÖ±½ÓÔËÓÃÎÊÌ⣬ֱ½Ó¸ù¾Ý¹«Ê½·ÖÎö¼´¿É£¬×¢ÒâÕÆÎÕ¿ØÖƱäÁ¿·¨µÄÔËÓã¬Í¬Ê±µ±ÐÄÕýÈ·µÄÔËË㣮

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
13£®Ä³Í¬Ñ§Éè¼ÆÁËÒ»¸ö̽¾¿Ð¡³µµÄ¼ÓËÙ¶ÈaÓëС³µËùÊÜÀ­Á¦F¼°ÖÊÁ¿m¹ØÏµµÄʵÑ飬ͼ£¨a£©ÎªÊµÑé×°Öüòͼ£®£¨ËùÓý»±äµçÁ÷µÄƵÂÊΪ50Hz£©

£¨1£©¹ØÓÚС³µËùÊܵĺÏÁ¦£¬ÏÂÁÐÐðÊöÖÐÕýÈ·µÄÊÇD
A£®Ð¡³µËùÊܵĺÏÁ¦¾ÍÊÇËù¹ÒµõÅ̺͹³ÂëµÄÖØÁ¦
B£®Ð¡³µËùÊܺÏÁ¦µÄ´óСµÈÓÚµõÅÌÓë¹³Âëͨ¹ýϸÉþ¶ÔС³µÊ©¼ÓµÄÀ­Á¦
C£®Ö»ÓÐÆ½ºâĦ²ÁÁ¦ºó£¬Ð¡³µËùÊܺÏÁ¦²ÅµÈÓÚϸÉþ¶ÔС³µµÄÀ­Á¦
D£®Ö»ÓÐÆ½ºâĦ²ÁÁ¦Ö®ºó£¬ÇÒµ±Ð¡³µÖÊÁ¿MÔ¶´óÓÚµõÅÌÓëâhÂëµÄ×ÜÖÊÁ¿Ê±£¬Ð¡³µËùÊܺÏÁ¦µÄ´óС¿ÉÈÏΪµÈÓÚµõÅÌÓëâhÂëµÄÖØÁ¦
£¨2£©Í¼£¨b£©ÎªÄ³´ÎʵÑéµÃµ½µÄÖ½´ø£¬ÊµÑéÊý¾ÝÈçͼ£¬Í¼ÖÐÏàÁÚ¼ÆÊýµãÖ®¼ä»¹ÓÐ4¸öµãδ»­³ö£¬¸ù¾ÝÖ½´ø¿ÉÇó³öС³µµÄ¼ÓËÙ¶È´óСΪ0.510m/s2£®£¨±£ÁôÈýλÓÐЧÊý×Ö£©
£¨3£©±£³ÖɰºÍɰͰÖÊÁ¿²»±ä£¬¸Ä±äС³µÖÊÁ¿m£¬·Ö±ðµÃµ½Ð¡³µ¼ÓËÙ¶ÈaÓëÖÊÁ¿m¼°¶ÔÓ¦µÄ$\frac{1}{m}$£¬Êý¾ÝÈç±í£º
ʵÑé´ÎÊý12345678
С³µ¼ÓËÙ¶Èa/m•s-20.6330.5720.4970.4180.3320.2500.1670.101
С³µÖÊÁ¿m/kg0.250.290.330.400.500.711.001.67
С³µÖÊÁ¿µ¹Êý$\frac{1}{m}$/kg-14.003.453.032.502.001.411.000.60
ÇëÔÚͼ£¨c£©µÄ·½¸ñ×ø±êÖ½Öл­³öa-$\frac{1}{m}$ͼÏߣ¬¸ÃʵÑéµÃµ½µÄ ¼ÓËÙ¶ÈÓëÖÊÁ¿µÄ¹ØÏµa=$\frac{1}{3m}$
£¨4£©±£³ÖС³µÖÊÁ¿²»±ä£¬¸Ä±äɰºÍɰͰÖÊÁ¿£¬Ò»Î»Í¬Ñ§¸ù¾ÝʵÑéÊý¾Ý×÷³öÁ˼ÓËÙ¶ÈaËæÀ­Á¦FµÄ±ä»¯Í¼ÏßÈçͼ£¨d£©Ëùʾ£®¸ÃͼÏß²»Í¨¹ýÔ­µã£¬ÆäÖ÷ÒªÔ­ÒòÊÇûÓÐÆ½ºâĦ²ÁÁ¦»òĦ²ÁÁ¦Æ½ºâ²»¹»£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø