ÌâÄ¿ÄÚÈÝ
(Ñ¡ÐÞÄ£¿é3-3)
£¨1£©ÒÔÏÂ˵·¨ÕýÈ·µÄÊÇ ¡ø
A£®µ±Á½¸ö·Ö×Ó¼äµÄ¾àÀëΪr0(ƽºâλÖÃ)ʱ£¬·Ö×ÓÊÆÄÜ×îС
B£®²¼ÀÊÔ˶¯·´Ó³ÁË»¨·ÛС¿ÅÁ£ÄÚ²¿·Ö×ÓµÄÎÞ¹æÔòÔ˶¯
C£®Ò»µÎÓÍËá¾Æ¾«ÈÜÒºÌå»ýΪV£¬ÔÚË®ÃæÉÏÐγɵĵ¥·Ö×ÓÓÍÄ¤Ãæ»ýΪS£¬ÔòÓÍËá·Ö×ÓµÄÖ±¾¶![]()
D£®Î¶ȡ¢Ñ¹Á¦¡¢µç´Å×÷ÓõȿÉÒԸıäÒº¾§µÄ¹âѧÐÔÖÊ
£¨2£©ÈçͼËùʾ£¬Ò»Ö±Á¢µÄÆø¸×ÓÃÒ»ÖÊÁ¿ÎªmµÄ»îÈû·â±ÕÒ»¶¨Á¿µÄÀíÏëÆøÌ壬»îÈûºá½ØÃæ»ýΪS£¬Æû¸×Äڱڹ⻬ÇҸױÚÊǵ¼Èȵģ®¿ªÊ¼»îÈû±»¹Ì¶¨£¬´ò¿ª¹Ì¶¨ÂÝ˨K£¬»îÈûÉÏÉý£¬¾¹ý×ã¹»³¤Ê±¼äºó£¬»îÈûÍ£ÔÚBµã£¬Ôò»îÈûÍ£ÔÚBµãʱ¸×ÄÚ·â±ÕÆøÌåµÄѹǿΪ ¡ø £¬Ôڸùý³ÌÖУ¬¸×ÄÚÆøÌå ¡ø £¨Ìî¡°ÎüÈÈ¡±»ò¡°·ÅÈÈ¡±£©£®£¨ÉèÖÜΧ»·¾³Î¶ȱ£³Ö²»±ä£¬ÒÑÖªAB=h£¬´óÆøÑ¹Ç¿Îªp0£¬ÖØÁ¦¼ÓËÙ¶ÈΪg£©
£¨3£©¡°Ë®Á¢·½¡±¹ú¼ÒÓÎÓ¾ÖÐÐÄÊDZ±¾©Îª2008ÄêÏļ¾°ÂÔË»áÐÞ½¨µÄÖ÷ÓÎÓ¾¹Ý£®Ë®Á¢·½ÓÎÓ¾¹Ý¹²ÓÐ8ÌõÓ¾µÀµÄ¹ú¼Ê±ê×¼±ÈÈüÓÃÓÎÓ¾³Ø£¬ÓÎÓ¾³Ø³¤50 m¡¢¿í25 m¡¢Ë®Éî3 m£®ÉèË®µÄĦ¶ûÖÊÁ¿ÎªM£½1.8¡Á10-2kg£¯mol£¬ÊÔ¹ÀËã¸ÃÓÎÓ¾³ØÖÐË®·Ö×ÓÊý£®
![]()
£¨1£©AD£¨4·Ö£©
£¨2£©
£¨2·Ö£©¡¡¡¡ÎüÈÈ £¨2·Ö£©
£¨3£©ÉèË®µÄÃܶÈΪ¦Ñ£¬ÓÎÓ¾³ØÖÐË®µÄÖÊÁ¿Îªm £¬°¢·ü¼ÓµÂÂÞ³£ÊýΪNA £¬ÓÎÓ¾³ØÖÐË®µÄ×ÜÌå»ýΪ V=50¡Á25¡Á3m3=3.75¡Á103 m3£¨1·Ö£©
ÔòÓÎÓ¾³ØÖÐË®µÄÎïÖʵÄÁ¿Îªn=m£¯M=¦ÑV£¯M£¨1·Ö£©
Ëùº¬µÄË®·Ö×ÓÊýΪN1=nNA=¦ÑVNA£¯M=1.0¡Á103¡Á3.75¡Á103¡Á6.02¡Á1023£¯(1.8¡Á10£2)¸ö=1.3¡Á1032¸ö£¨2·Ö£©