ÌâÄ¿ÄÚÈÝ

9£®£¨1£©ÔÚ×ö¡°ÀûÓõ¥°Ú²âÖØÁ¦¼ÓËÙ¶È¡±ÊµÑéÖУ¬Ä³Í¬Ñ§ÏȲâµÃ°ÚÏß³¤Îª89.2cm£¬°ÚÇòÖ±¾¶Èçͼ¼×Ëùʾ£¬È»ºóÓÃÃë±í¼Ç¼Á˵¥°ÚÕñ¶¯30´ÎÈ«Õñ¶¯ËùÓõÄʱ¼äÈçͼÒÒËùʾ£¬Ôò£¨1£©¸Ãµ¥°ÚµÄ°Ú³¤Îª90.17cm£¬Ãë±íËùʾ¶ÁÊýΪ228.6s£®
£¨2£©Èç¹û¸Ãͬѧ²âµÃµÄgֵƫ´ó£¬¿ÉÄܵÄÔ­ÒòÊÇAD
A£®²â°ÚÏß³¤Ê±¼ÇÈëµÄÊǰÚÇòµÄÖ±¾¶
B£®ÊµÑéÊÒÔÚ¸ßɽÉÏ£¬¸ß³öº£Æ½ÃæÌ«¸ß
C£®µ¥°ÚËùÓðÚÇòÌ«ÖØ
D£®ÊÔÑéÖÐÎó½«29´ÎÈ«Õñ¶¯ÊýΪ30´Î
£¨3£©ÎªÁËÌá¸ßʵÑ龫¶È£¬ÔÚÊÔÑéÖпɸı伸´Î°Ú³¤l£¬²â³öÏàÓ¦µÄÖÜÆÚT£¬´Ó¶øµÃ³öÒ»×é¶ÔÓ¦µÄlÓëTµÄÊýÖµ£¬ÔÙÒÔlΪºá×ø±êT2Ϊ×Ý×ø±ê£¬½«ËùµÃÊý¾ÝÁ¬³ÉÖ±ÏßÈçͼËùʾ£¬Ôò²âµÃµÄÖØÁ¦¼ÓËÙ¶Èg=9.87m/s2£®£¨±£ÁôÈýλÓÐЧÊý×Ö£©

·ÖÎö £¨1£©Óα꿨³ßÏȶÁ³öÖ÷³ßµÄ¿Ì¶È£¬È»ºó¶Á³öÓαê³ßµÄ¿Ì¶È£¬¶þÕߵĺͼ´ÎªËùÇó£®
Ãë±íÏȶÁ·ÖÕë¶ÁÊý£¬ÔÙ¶ÁÃëÕë¶ÁÊý£¬Á½ÕßÏà¼Ó£®
£¨2£©¸ù¾Ýµ¥°ÚµÄÖÜÆÚ¹«Ê½T=$2¦Ð\sqrt{\frac{L}{g}}$£¬µÃµ½ÖØÁ¦¼ÓËٶȵıí´ïʽg=$\frac{4{¦Ð}^{2}L}{{T}^{2}}$£¬¿É·ÖÎögֵƫС¿ÉÄܵÄÔ­Òò£®
£¨3£©¸ù¾ÝÖØÁ¦¼ÓËٶȵıí´ïʽg=$\frac{4{¦Ð}^{2}L}{{T}^{2}}$£¬ÓÉÊýѧ֪ʶ·ÖÎöÖ±ÏßµÄбÂÊÓëgµÄ¹ØÏµ£®

½â´ð ½â£º£¨1£©ÓÉͼ¿ÉÖª£¬Ö÷³ßµÄ¿Ì¶ÈΪ19mm£¬Óαê³ßµÄµÚ4¸ö¿Ì¶ÈÓëÉÏ±ß¶ÔÆë£¬ËùÒԸöÁÊýΪ£º
D=19mm+4¡Á0.1mm=19.4mm=1.94cm
 µ¥°ÚµÄ°Ú³¤L=°ÚÏß³¤+ÇòµÄ°ë¾¶=89.2cm+$\frac{1.94}{2}$cm=90.17 cm  
Ãë±íµÄ¶ÁÊýΪ£º3.5¡Á60+18.6=228.6s
£¨2£©¸ù¾Ýµ¥°ÚµÄÖÜÆÚ¹«Ê½T=2$¦Ð\sqrt{\frac{L}{g}}$µÃ£ºg=$\frac{4{¦Ð}^{2}L}{{T}^{2}}$£®
A£®¼Ç¼°Ú³¤Ê±Î󽫰ÚÇòµÄÖ±¾¶×÷Ϊ°ë¾¶£¬°Ú³¤Æ«´ó£¬ÓÉÉÏʽµÃÖª²âµÃµÄgӦƫ´ó£¬¹ÊAÕýÈ·£®
B£®ÊµÑéÊÒÔÚ¸ßɽÉÏ£¬¸ß³öº£Æ½ÃæÌ«¸ß£¬¿ÉÖª²âµÃµÄgֵƫС£¬¹ÊB´íÎó£»
C£®Óɹ«Ê½¿ÉÖª£¬°ÚÇòµÄÖÊÁ¿¶Ô²âÁ¿ÖµÃ»ÓÐÓ°Ï죬¹ÊC´íÎó£»
D£®ÊµÑéÖÐÎó½«29´ÎÈ«Õñ¶¯ÊýΪ30´Î£¬ÓÉT=$\frac{t}{n}$Ëã³öµÄÖÜÆÚTƫС£¬ÓÉÉÏʽ¿ÉÖª²âµÃµÄgֵƫ´ó£¬¹ÊDÕýÈ·£®
¹ÊÑ¡£ºAD
£¨3£©¸ù¾Ýµ¥°ÚµÄÖÜÆÚ¹«Ê½T=2$¦Ð\sqrt{\frac{L}{g}}$µÃ£ºg=$\frac{4{¦Ð}^{2}L}{{T}^{2}}$=$\frac{4{¦Ð}^{2}¡Á1}{4}={¦Ð}^{2}¡Ö9.87$m/s2£®
¹Ê´ð°¸Îª£º£¨1£©90.17cm£¬228.6£¨2£©AD£¨3£©9.87m/s2

µãÆÀ ±¾Ì⿼²éÁË¡°ÀûÓõ¥°Ú²âÖØÁ¦¼ÓËÙ¶È¡±ÊµÑéÖÐÊý¾Ý¶ÁÊý·½·¨£¬ÕÆÎÕµ¥°ÚµÄÖÜÆÚ¹«Ê½£¬²¢ÒªÓÐÇ¨ÒÆÄÜÁ¦£¬ÓÃÀ´½â¾öʵ¼ÊÎÊÌ⣮

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø