ÌâÄ¿ÄÚÈÝ
(¼×)ΪijͬѧÀûÓðëÔ²Ðβ£Á§×©²â¶¨²£Á§ÕÛÉäÂÊnµÄ×°ÖÃʾÒâͼ.ËûÈùâ´Ó¿ÕÆøÉäÏò²£Á§×©,ÔÚÕýÈ·²Ù×÷ºó,ËûÀûÓòâ³öµÄÊý¾Ý×÷³öÁËͼ(ÒÒ)ËùʾµÄÕÛÉä½ÇÕýÏÒ(sin r)ÓëÈëÉä½ÇÕýÏÒ(sin i)µÄ¹ØÏµÍ¼Ïñ.ÔòÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ(¡¡¡¡)
![]()
A.¸Ã²£Á§µÄÕÛÉäÂÊn=![]()
B.¸Ã²£Á§µÄÕÛÉäÂÊn=1.5
C.¹âÓÉ¿ÕÆø½øÈë¸Ã²£Á§×©Öд«²¥Ê±,¹â²¨ÆµÂʱäΪÔÀ´µÄ
±¶
D.¹âÓÉ¿ÕÆø½øÈë¸Ã²£Á§×©Öд«²¥Ê±,¹â²¨²¨³¤±äΪÔÀ´µÄ1.5±¶
B½âÎö:ÓÉÕÛÉ䶨ÂÉn=sin i/ sin r¿ÉÖªÕÛÉä½ÇÕýÏÒ(sin r)ÓëÈëÉä½ÇÕýÏÒ(sin i)µÄ¹ØÏµÍ¼ÏñбÂʵĵ¹Êý±íʾÕÛÉäÂÊ,ËùÒÔn=3/2=1.5,Ñ¡ÏîA´íÎó,BÕýÈ·;¹âÓÉ¿ÕÆø½øÈë¸Ã²£Á§×©Öд«²¥Ê±,¹â²¨ÆµÂʲ»±ä,ÓÉn=
,v=f¦Ë¿ÉÖª,¹â²¨²¨³¤±äΪÔÀ´µÄ
,Ñ¡ÏîC¡¢D´íÎó.
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿