ÌâÄ¿ÄÚÈÝ
ÔÚ¡°²â¶¨Ä³µç×èË¿µÄµç×èÂÊ¡±ÊµÑéÖÐ
¢ÙÓÃÂÝÐý²â΢Æ÷²âÁ¿µç×è˿ֱ¾¶£¬ÈçͼËùʾ£¬Ôòµç×èË¿µÄÖ±¾¶ÊÇ________ mm
¢ÚÓöàÓñíµÄÅ·Ä·µ²´Ö²âµç×èË¿µÄ×èÖµ£¬ÒÑÖªµç×èË¿×èÖµºÜ´ó£¬Ô¼Îª20k¦¸¡£ÏÂÃæ¸ø³öµÄ²Ù×÷²½ÖèÖУ¬ºÏÀíµÄʵÑé²½Öè˳ÐòÊÇ__________(ÌîдÏàÓ¦µÄ×Öĸ)
a£®½«Á½±í±Ê¶Ì½Ó£¬µ÷½ÚÅ·Ä·µ²µ÷ÁãÐýťʹָÕë¶Ô×¼¿Ì¶ÈÅÌÉÏÅ·Ä·µ²µÄÁã¿Ì¶È
b£®½«Á½±í±Ê·Ö±ðÁ¬½Óµ½±»²âµç×èË¿µÄÁ½¶Ë£¬¶Á³ö×èÖµºó£¬¶Ï¿ªÁ½±í±Ê
c£®ÐýתѡÔñ¿ª¹Ø£¬Ê¹Æä¼â¶Ë¶Ô׼ŷķµ²µÄ¡°¡Á1 k¡±µ²
d£®ÐýתѡÔñ¿ª¹Ø£¬Ê¹Æä¼â¶Ë¶Ô×¼¡°OFF¡±µ²£¬²¢°Î³öÁ½±í±Ê
¢ÛÈôÓõçÁ÷±íºÍµçѹ±í¾«È·²âÁ¿´Ëµç×èË¿µÄ×èÖµ£¬ÊµÑéÊÒÌṩÏÂÁпɹ©Ñ¡ÓÃµÄÆ÷²Ä£º
µçѹ±íV(Á¿³Ì3 V£¬ÄÚ×èÔ¼50 k¦¸)
µçÁ÷±íA1(Á¿³Ì200 ¦ÌA£¬ÄÚ×èÔ¼200 ¦¸)
µçÁ÷±íA2(Á¿³Ì5 mA£¬ÄÚ×èÔ¼20 ¦¸)
µçÁ÷±íA3(Á¿³Ì0.6 A£¬ÄÚ×èÔ¼1 ¦¸)
»¬¶¯±ä×èÆ÷R(×î´óÖµ500 ¦¸)
µçÔ´E(µç¶¯ÊÆ4.5 V£¬ÄÚ×èÔ¼0.2 ¦¸)
¿ª¹ØSµ¼Ïß
a£®ÔÚËùÌṩµÄµçÁ÷±íÖÐӦѡÓÃ________(Ìî×Öĸ´úºÅ)£®
b£®ÔÚÐéÏß¿òÖл³ö²âµç×èµÄʵÑéµç·£®
¢Ü¸ù¾ÝÉÏÃæ²âµÃµÄÊý¾Ý£¬¼´¿ÉÇó³ö¸Ãµç×èË¿µÄµç×èÂÊ£¬Èô²âµÃµç×èË¿³¤¶ÈΪL£¬Ö±¾¶Îªd£¬ÔÚ¢ÛÖÐÕýÈ·²Ù×÷ºóµÃµ½µçѹ±íʾÊýΪU£¬µçÁ÷±íʾÊýΪI£¬Ôò¸Ã½ðÊôË¿µÄµç×èÂÊΪ__________£®
![]()
¢Ù0.641¡«0.643 ¢Úcabd¡¡
¢Ûa.A1 b.²âµç×èµÄʵÑéµç·Èçͼ
![]()
¢Ü![]()
![]()