ÌâÄ¿ÄÚÈÝ

12£®¡°ÉñÖÛÆßºÅ¡±ÔØÈË·É´¬·¢ÉäÉý¿Õºó£¬·ÉÐÐÁË2Ìì20Сʱ27·ÖÖÓ£¬ÈƵØÇòÔËÐÐ45Ȧ£¬·µ»Ø²Õ˳Àû·µ»Ø×Ž£®Õâ±êÖ¾×ÅÎÒ¹úº½ÌìÊÂÒµÓÖÂõÉÏÁËÒ»¸öÐĄ̂½×£¬¼Ù¶¨Õý³£ÔËÐеÄÉñÖÛÆßºÅ·É´¬ºÍͨÐÅÎÀÐÇ£¨Í¬²½ÎÀÐÇ£©×öµÄ¶¼ÊÇÔÈËÙÔ²ÖÜÔ˶¯£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®·É´¬µÄÏßËٶȱÈͨÐÅÎÀÐǵÄÏßËÙ¶ÈС
B£®·É´¬µÄ½ÇËٶȱÈͨÐÅÎÀÐǵĽÇËÙ¶ÈС
C£®·É´¬µÄÔËÐÐÖÜÆÚ±ÈͨÐÅÎÀÐǵÄÔËÐÐÖÜÆÚС
D£®·É´¬µÄÏòÐļÓËٶȱÈͨÐÅÎÀÐǵÄÏòÐļÓËÙ¶ÈС

·ÖÎö ¸ù¾ÝÍòÓÐÒýÁ¦ÌṩÏòÐÄÁ¦£¬¸ù¾ÝÖÜÆÚµÄ´óС¹ØÏµ±È½Ï¹ìµÀ°ë¾¶£¬´Ó¶ø±È½Ï³öÏßËÙ¶È¡¢½ÇËÙ¶È¡¢ÏòÐļÓËٶȵĴóС¹ØÏµ£®

½â´ð ½â£ºÓÉÌâÒâ¿ÉÖª£¬¡°ÉñÖÛÆßºÅ¡±µÄÖÜÆÚ´óԼΪT=$\frac{68.5}{45}h¡Ö1.5h$£¬Ð¡ÓÚͬ²½ÎÀÐǵÄÖÜÆÚ£¬¸ù¾Ý$¦Ø=\frac{2¦Ð}{T}$Öª£¬·É´¬µÄ½ÇËÙ¶È´óÓÚͨÐÅÎÀÐǵĽÇËÙ¶È£¬¹ÊB´íÎó£¬CÕýÈ·£®
¸ù¾Ý$G\frac{Mm}{{r}^{2}}=mr\frac{4{¦Ð}^{2}}{{T}^{2}}$Öª£¬T=$\sqrt{\frac{4{¦Ð}^{2}{r}^{3}}{GM}}$£¬ÒòΪ¡°ÉñÖÛÆßºÅ¡±µÄÖÜÆÚСÓÚͬ²½ÎÀÐǵÄÖÜÆÚ£¬Ôò¡°ÉñÖÛÆßºÅ¡±µÄ¹ìµÀ°ë¾¶Ð¡ÓÚͬ²½ÎÀÐǵĹìµÀ°ë¾¶£®
¸ù¾Ý$G\frac{Mm}{{r}^{2}}=ma=m\frac{{v}^{2}}{r}$Öª£¬a=$\frac{GM}{{r}^{2}}$£¬v=$\sqrt{\frac{GM}{r}}$£¬Öª·É´¬µÄÏßËٶȱÈͨÐÅÎÀÐǵÄÏßËٶȴ󣬷ɴ¬µÄÏòÐļÓËٶȱÈͨÐÅÎÀÐǵÄÏòÐļÓËٶȴ󣬹ÊA¡¢D´íÎó£®
¹ÊÑ¡£ºC£®

µãÆÀ ½â¾ö±¾ÌâµÄ¹Ø¼üÕÆÎÕÍòÓÐÒýÁ¦ÌṩÏòÐÄÁ¦ÕâÒ»ÖØÒªÀíÂÛ£¬ÖªµÀÏßËÙ¶È¡¢½ÇËÙ¶È¡¢ÏòÐļÓËÙ¶È¡¢ÖÜÆÚÓë¹ìµÀ°ë¾¶µÄ¹ØÏµ£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø