题目内容


如图所示,将长50cm、质量为10g的均匀金属棒ab的两端用两只相同的弹簧悬挂成水平状态,位于垂直纸面向里的匀强磁场中,当金属棒中通过0.4A的电流时,弹簧恰好不伸长,求:(g取10m/s2)                     

(1)匀强磁场中磁感应强度是多大?                                                                        

(2)当金属棒中通过0.2A由a到b的电流时,弹簧伸长为1cm,如果电流方向由b到a,而电流大小不变,弹簧又伸长是多少?                                                                                                                       

                                                                                  

                                                                                                                                  


(1)由题可知  F=mg  即  BIL=mg

解之得,

(2)当电流由a→b

 F+2kx=mg    即      BIL+2kx=mg

解之得,N/m=2.5N/m

当电流由b→a

mg+F=2kx1

解之得,==0.03m=3cm

答:(1)匀强磁场中磁感应强度是0.5T;

(2)当金属棒中通过0.2A由a到b的电流时,弹簧伸长为1cm,如果电流方向由b到a,而电流大小不变,弹簧又伸长是3cm.


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