ÌâÄ¿ÄÚÈÝ
ÈçͼK44£10Ëùʾ£¬Í¼ÏßaÊÇÏßȦÔÚÔÈÇ¿´Å³¡ÖÐÔÈËÙת¶¯Ê±²úÉúµÄÕýÏÒ½»Á÷µç
µÄͼÏ󣬵±µ÷ÕûÏßȦתËÙºó£¬Ëù²úÉúµÄÕýÏÒ½»Á÷µçµÄͼÏóÈçͼÏßbËùʾ£®ÒÔϹØÓÚÕâÁ½¸öÕýÏÒ½»Á÷µçµÄ˵·¨ÖÐÕýÈ·µÄÊÇ(¡¡¡¡)
A£®ÏßȦÏȺóÁ½´ÎתËÙÖ®±ÈΪ1¡Ã2
B£®½»Á÷µçaµÄµçѹ˲ʱֵu£½10sin0.4¦Ðt V![]()
C£®½»Á÷µçbµÄµçѹ·åֵΪ
V
D£®ÔÚͼÖÐt£½0ʱ¿Ì´©¹ýÏßȦµÄ´ÅͨÁ¿ÎªÁã
![]()
ͼK44£10
C¡¡[½âÎö] ÏßȦתËÙµ÷ÕûºóTa¡ÃTb£½2¡Ã3£¬ÏßȦתËÙÖ®±ÈΪ3¡Ã2£¬Ñ¡ÏîA´íÎó£»ÓÉͼÏóÖª£¬½»Á÷µçaÏßȦת¶¯µÄ½ÇƵÂʦØa£½
£½5¦Ð rad/s£¬½»Á÷µçaµÄµçѹ˲ʱֵu£½10sin5¦Ðt V£¬Ñ¡ÏîB´íÎó£»½»Á÷µç¶¯ÊƵķåÖµEm£½nBS¦Ø£¬ËùÒÔµç¶¯ÊÆ·åÖµÖ®±ÈΪ3¡Ã2£¬½»Á÷µçbµÄµçѹ·åֵΪ
V£¬Ñ¡ÏîCÕýÈ·£»ÓÉͼÏóÖª£¬t£½0ʱ¿ÌÏßȦλÓÚÖÐÐÔÃæ£¬´©¹ýÏßȦµÄ´ÅͨÁ¿×î´ó£¬Ñ¡ÏîD´íÎó£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿