ÌâÄ¿ÄÚÈÝ

 (2013Òø´¨Ò»ÖÐÆÚÄ©)ÏÖ´ú¿ÆÑ§Ñо¿Öг£Óõ½¸ßËÙµç×Ó£¬µç×Ó¸ÐÓ¦¼ÓËÙÆ÷¾ÍÊÇÀûÓøÐÉúµç³¡¼ÓËÙµç×ÓµÄÉ豸¡£µç×Ó¸ÐÓ¦¼ÓËÙÆ÷Ö÷ÒªÓÐÉÏ¡¢Ïµç´ÅÌú´Å¼«ºÍ»·ÐÎÕæ¿ÕÊÒ×é³É¡£µ±µç´ÅÌúÈÆ×éͨÒԱ仯µÄµçÁ÷ʱ,²úÉú±ä»¯µÄ´Å³¡£¬´©¹ýÕæ¿ÕºÐËù°üΧµÄÇøÓòÄڵĴÅͨÁ¿Ò²ËæÊ±¼ä±ä»¯£¬ÕâÊ±Õæ¿ÕºÐ¿Õ¼äÄھͲúÉú¸ÐÓ¦ÎÐÐýµç³¡£¬µç×Ó½«ÔÚÎÐÐýµç³¡×÷ÓÃϵõ½¼ÓËÙ¡£ÈçͼËùʾ£¨ÉÏͼΪ²àÊÓͼ¡¢ÏÂÍ¼ÎªÕæ¿ÕÊҵĸ©ÊÓͼ£©£¬Èôµç×Ó±»¡°Ô¼Êø¡±Ôڰ뾶ΪRµÄÔ²ÖÜÉÏÔ˶¯£¬µ±µç´ÅÌúÈÆ×éͨÓÐͼÖÐËùʾµÄµçÁ÷ʱ£º

A. Èôµç×ÓÑØÄæÊ±ÕëÔ˶¯£¬±£³ÖµçÁ÷µÄ·½Ïò²»±ä£¬µ±µçÁ÷Ôö´óʱ£¬µç×Ó½«¼ÓËÙ

B. Èôµç×ÓÑØË³Ê±ÕëÔ˶¯£¬±£³ÖµçÁ÷µÄ·½Ïò²»±ä£¬µ±µçÁ÷Ôö´óʱ£¬µç×Ó½«¼ÓËÙ

C. Èôµç×ÓÑØÄæÊ±ÕëÔ˶¯£¬±£³ÖµçÁ÷µÄ·½Ïò²»±ä£¬µ±µçÁ÷¼õСʱ£¬µç×Ó½«¼ÓËÙ

D£®±»¼ÓËÙʱµç×Ó×öÔ²ÖÜÔ˶¯µÄÖÜÆÚ²»±ä

´ð°¸£ºA

½âÎö£ºµ±µç´ÅÌúÈÆ×éͨÓÐͼÖÐËùʾµÄµçÁ÷ʱ£¬Óɰ²ÅඨÔò£¬½«²úÉúÏòÉϵĴų¡£¬µ±µç´ÅÌúÈÆ×éÖеçÁ÷Ôö´óʱ£¬¸ù¾ÝÀã´Î¶¨ÂÉ£¬ÕâÊ±Õæ¿ÕºÐ¿Õ¼äÄھͲúÉú˳ʱÕë·½ÏòµÄ¸ÐÓ¦ÎÐÐýµç³¡£¬µç×ÓÑØÄæÊ±ÕëÔ˶¯£¬µç×Ó½«¼ÓËÙ£¬Ñ¡ÏîAÕýÈ·BC´íÎó£»ÓÉÓÚµç×Ó±»¡°Ô¼Êø¡±Ôڰ뾶ΪRµÄÔ²ÖÜÉÏÔ˶¯£¬µç×Ó¼ÓËÙ£¬±»¼ÓËÙʱµç×Ó×öÔ²ÖÜÔ˶¯µÄÖÜÆÚ¼õС£¬Ñ¡ÏîD´íÎó¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

 (2013Òø´¨Ò»ÖÐÆÚÄ©)ÖйúÁÉÄþºÅº½¿Õĸ½¢ÊÇÖйúÈËÃñ½â·Å¾üº£¾üµÄµÚÒ»ËÒº½¿Õĸ½¢¡£2012Äê9ÔÂ25ÈÕ£¬¸Ã½¢Õýʽ¼ÓÈëÖйúº£¾üÐòÁС£11ÔÂ25ÈÕ£¬¼ß-15½¢ÔØ»úÔÚº½Ä¸Éϳɹ¦Æð½µÁË£¬ÎªÖйúº½Ä¸Õ½¶·Á¦µÄÐγÉÂõ³öÁ˼«Îª¹Ø¼üµÄÒ»²½¡£¼ß-15·É»úÊÇÎÒ¹ú×ÔÐÐÉè¼ÆÑÐÖÆµÄÊ×Ðͽ¢ÔضàÓÃ;ս¶·»ú£¬¾ßÓÐÍêÈ«µÄ×ÔÖ÷֪ʶ²úȨ¡£º½¿Õĸ½¢ÉÏµÄÆð·ÉÅܵÀ¿ÉÒÔ¼ò»¯ÎªÈçͼËùʾ£¬¼ÙÉ躽¿Õĸ½¢ÉÏµÄÆð·ÉÅܵÀÓɳ¤¶ÈΪL1=1.6¡Á102 m µÄˮƽÅܵÀºÍ³¤¶ÈΪL2 = 20 mµÄÇãбÅܵÀÁ½²¿·Ö×é³É¡£Ë®Æ½ÅܵÀÓëÇãбÅܵÀÄ©¶ËµÄ¸ß¶È²îh = 4.0 m¡£½¢ÔØ»úÖÊÁ¿Îªm = 2.0¡Á104 kgµÄ·É»ú,Æä·¢¶¯»úµÄÍÆÁ¦´óСºãΪF = 1.2¡Á105 N£¬·½ÏòÓëËÙ¶È·½ÏòÏàͬ£¬ÔÚÔ˶¯¹ý³ÌÖзɻúÊܵ½µÄƽ¾ù×èÁ¦´óСΪ·É»úÖØÁ¦µÄ0.1±¶¡£¼ÙÉ躽ĸ´¦ÓÚ¾²Ö¹×´Ì¬£¬·É»úÖÊÁ¿ÊÓΪ²»±ä²¢¿É¿´³ÉÖʵã,È¡g = 10 m/s2¡£

£¨1£©Çó·É»úµ½´ïÇãбÅܵÀÄ©¶ËʱµÄËÙ¶È´óС£»

£¨2£©ÎªÁËʹ·É»úÔÚÇãбÅܵÀµÄÄ©¶Ë´ïµ½Æð·ÉËÙ¶È100 m/s£¬Íâ½ç»¹ÐèÒªÔÚÕû¸öˮƽ¹ìµÀ¶Ô·É»úÊ©¼ÓÖúÍÆÁ¦£¬ÇóÖúÍÆÁ¦FÍÆµÄ´óС¡£

(2013Òø´¨Ò»ÖÐÆÚÄ©)ijͬѧ×ö¡°Ì½¾¿¼ÓËÙ¶ÈÓëÁ¦¡¢ÖÊÁ¿¹ØÏµ¡±µÄʵÑé¡£Èçͼ¼×ËùʾÊǸÃͬѧ̽¾¿Ð¡³µ¼ÓËÙ¶ÈÓëÁ¦µÄ¹ØÏµµÄʵÑé×°Öã¬Ëû½«¹âµçÃŹ̶¨ÔÚˮƽ¹ìµÀÉϵÄBµã£¬Óò»Í¬ÖØÎïͨ¹ýϸÏßÀ­Í¬Ò»Ð¡³µ£¬Ã¿´ÎС³µ¶¼´ÓͬһλÖÃAÓɾ²Ö¹ÊÍ·Å£®¡¡ £¨1£©ÊµÑéÖпɽüËÆÈÏΪϸÏß¶ÔС³µµÄÀ­Á¦ÓëÖØÎïÖØÁ¦´óСÏàµÈ£¬ÔòÖØÎïµÄÖÊÁ¿mÓëС³µµÄÖÊÁ¿M¼äÓ¦Âú×ãµÄ¹ØÏµÎª¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ £»

£¨2£©ÈôÓÃÓα꿨³ß²â³ö¹âµçÃÅÕÚ¹âÌõµÄ¿í¶ÈdÈçͼÒÒËùʾ£¬Ôòd =¡¡¡¡¡¡ cm£»ÊµÑéʱ½«Ð¡³µ´ÓͼʾλÖÃÓɾ²Ö¹ÊÍ·Å£¬ÓÉÊý×Ö¼ÆÊ±Æ÷¶Á³öÕÚ¹âÌõͨ¹ý¹âµçÃŵÄʱ¼ä?t£¬ÔòС³µ¾­¹ý¹âµçÃÅʱµÄËÙ¶ÈΪ¡¡¡¡¡¡¡¡¡¡ £¨ÓÃ×Öĸ±íʾ£©£»

£¨3£©²â³ö¶à×éÖØÎïµÄÖÊÁ¿mºÍ¶ÔÓ¦ÕÚ¹âÌõͨ¹ý¹âµçÃŵÄʱ¼ä¦¤t£¬²¢Ëã³öÏàӦС³µ¾­¹ý¹âµçÃÅʱµÄËÙ¶Èv£¬Í¨¹ýÃèµã×÷³öv2¡ªmÏßÐÔͼÏó(Èçͼ±ûËùʾ)£¬´ÓͼÏߵõ½µÄ½áÂÛÊÇ£ºÔÚС³µÖÊÁ¿Ò»¶¨Ê±£¬_________________________________¡£

£¨4£©Ä³Í¬Ñ§ÔÚ×÷³öµÄv2¡ªmÏßÐÔͼÏó²»Í¨¹ý×ø±êÔ­µã,¿ªÊ¼ÊµÑéǰËûÓ¦²ÉÈ¡µÄ×ö·¨ÊÇ(¡¡ )

A£®½«²»´ø»¬Âֵľ°åÒ»¶ËÊʵ±µæ¸ß£¬Ê¹Ð¡³µÔÚ¹³ÂëÀ­¶¯ÏÂÇ¡ºÃ×öÔÈËÙÔ˶¯

B£®½«²»´ø»¬Âֵľ°åÒ»¶ËÊʵ±µæ¸ß£¬Ê¹Ð¡³µÔÚ¹³ÂëÀ­¶¯ÏÂÇ¡ºÃ×öÔȼÓËÙÔ˶¯

C£®½«²»´ø»¬Âֵľ°åÒ»¶ËÊʵ±µæ¸ß£¬ÔÚ²»¹Ò¹³ÂëµÄÇé¿öÏÂʹС³µÇ¡ºÃ×öÔÈËÙÔ˶¯


D£®½«²»´ø»¬Âֵľ°åÒ»¶ËÊʵ±µæ¸ß£¬ÔÚ²»¹Ò¹³ÂëµÄÇé¿öÏÂʹС³µÇ¡ºÃ×öÔȼÓËÙÔ˶¯

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø