ÌâÄ¿ÄÚÈÝ

7£®»¬É³ÊǹúÄÚÐÂÐ˵ÄÒ»ÖÖÂÃÓÎÏîÄ¿£®ÈçͼËùʾ£¬A¡¢BÊÇɳµÀÅÔͬһ²àµÄÁ½¸ö¹Ì¶¨×®£¬Á½×®Á¬ÏßÓëɳµÀƽÐУ¬¼äΪ5L£¬É³µÀ½üËÆÎªÓëË®Æ½Ãæ³É¦È½ÇµÄÒ»¸öÐ±Ãæ£®Ò»ÈË´ø×ź¢×Ó×øÔÚ³¤ÎªLµÄ³¤·½Ðλ¬°åÉÏ£¬´ÓɳµÀÉ϶ËÔȼÓËÙ»¬Ï£®ÔÚËûÃÇÏ»¬µÄ¹ý³ÌÖУ¬»¬°åǰ¶Ë¾­¹ý¹Ì¶¨×®AʱµÄËÙ¶ÈΪv£¬¾­¹ý¹Ì¶¨×®BʱµÄËÙ¶ÈΪ4v£®¹Ì¶¨×®µÄ´ÖϸºöÂÔ²»¼Æ£¬ÖØÁ¦¼ÓËÙ¶ÈΪg£®
£¨1£©Ç󻬰åÏ»¬µÄ¼ÓËÙ¶È£»
£¨2£©Ç󻬰åͨ¹ý¹Ì¶¨×®AµÄʱ¼ä£»
£¨3£©ÈôÈ˺ͻ¬°åµÄ×ÜÖÊÁ¿Îªm£¬ÇóËûÃÇÔÚÏ»¬¹ý³ÌÖÐÊܵ½µÄ×èÁ¦£®

·ÖÎö £¨1£©ÈËÏ»¬¹ý³ÌÊÇÔȼÓËÙÖ±ÏßÔ˶¯£¬¸ù¾ÝËÙ¶ÈÎ»ÒÆ¹ØÏµ¹«Ê½ÁÐʽÇó½â¼ÓËÙ¶È£»
£¨2£©¶Ô´ÓAµã¿ªÊ¼Ô˶¯LµÄ¹ý³Ì£¬¸ù¾ÝÎ»ÒÆÊ±¼ä¹ØÏµ¹«Ê½ÁÐʽ£»
£¨3£©¶ÔÈ˺ͻ¬°åÕûÌåÊÜÁ¦·ÖÎö£¬ÊÜÖØÁ¦¡¢Ö§³ÖÁ¦ºÍ×èÁ¦£¬¸ù¾ÝÅ£¶ÙµÚ¶þ¶¨ÂÉÁÐʽÇó½â×èÁ¦´óС£®

½â´ð ½â£º£¨1£©ÈËÏ»¬¹ý³ÌÊÇÔȼÓËÙÖ±ÏßÔ˶¯£¬¹Ê£º£¨4v£©2-v2=2a•5L£»
½âµÃ£ºa=$\frac{3{v}^{2}}{2L}$£»
£¨2£©¶Ô´ÓAµã¿ªÊ¼Ô˶¯LµÄ¹ý³Ì£¬¸ù¾ÝÎ»ÒÆÊ±¼ä¹ØÏµ¹«Ê½£¬ÓУºL=vt+$\frac{1}{2}a{t}^{2}$£»
½âµÃ£ºt=$\frac{2L}{3v}$£»
£¨3£©Ï»¬¹ý³ÌÖУºmgsin¦È-Ff=ma£»
ËùÒÔ£ºFf=mgsin¦È-$\frac{3m{v}^{2}}{2L}$£»
´ð£º£¨1£©»¬°åÏ»¬µÄ¼ÓËÙ¶ÈΪ$\frac{3{v}^{2}}{2L}$£»
£¨2£©»¬°åͨ¹ý¹Ì¶¨×®AµÄʱ¼äΪ$\frac{2L}{3v}$£»
£¨3£©ÈôÈ˺ͻ¬°åµÄ×ÜÖÊÁ¿Îªm£¬ËûÃÇÔÚÏ»¬¹ý³ÌÖÐÊܵ½µÄ×èÁ¦´óСΪmgsin¦È-$\frac{3m{v}^{2}}{2L}$£®

µãÆÀ ±¾ÌâÊÇÒÑÖªÔ˶¯Çé¿öÈ·¶¨ÊÜÁ¦Çé¿öµÄÎÊÌ⣬¹Ø¼üÊǸù¾ÝÔ˶¯Çé¿öÈ·¶¨¼ÓËÙ¶È£¬È»ºó¸ù¾ÝÅ£¶ÙµÚ¶þ¶¨ÂÉÁÐʽÇó½â£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø