ÌâÄ¿ÄÚÈÝ

19£®Á½¸öСÇò´ÓͬһµØµãͬʱ¿ªÊ¼Ô˶¯£¬Ò»¸ö×öƽÅ×Ô˶¯£¬ÁíÒ»¸ö×ö×ÔÓÉÂäÌåÔ˶¯£¬ÅÄµÃµÄÆµÉÁÕÕÆ¬ÈçÓÒͼËùʾ£¬²¢ÔÚÕÕÆ¬ÉϽ¨Á¢Ö±½Ç×ø±êϵ£¬¸ù¾Ý±ÈÀýËã³ö¸÷ÏñµãµÄʵ¼Ê×ø±ê£¬±êʾÔÚͼÉÏ£®
£¨1£©gÈ¡9.8m/s2£¬¸ù¾ÝƵÉÁÕÕÆ¬¼ÆËã³öƽÅ×Ô˶¯Ð¡ÇòÅ׳öʱµÄ³õËÙ¶È0.371m/s
£¨2£©Èç¹ûƽÅ×Ô˶¯µÄСÇò³õËÙ¶ÈΪv0£¬¾­¹ýͼÖбêʾµÄA¡¢BÁ½µãʱ£¬ËٶȵÄÊúÖ±·ÖÁ¿·Ö±ðΪvAy¡¢vBy£¬ÉèСÇòµÄÖÊÁ¿Îªm£¬Ôò´ÓAµ½BµÄ¹ý³ÌÖУ»Ôö¼ÓµÄ¶¯ÄÜΪ$\frac{1}{2}$m£¨${v}_{By}^{2}$-${v}_{Ay}^{2}$£©£¨ÓÃÌâÖзûºÅ±íʾ£©£¬ÎªÁËÑé֤ƽÅ×Ô˶¯µÄ¹ý³ÌÖлúеÄÜÊØºãÊÇ·ñÊØºã£¬Èç¹ûʵÑéÖиù¾ÝͼÖеÄÊúÖ±×ø±êÊý¾ÝÇó³öµÄ¼ÓËÙ¶ÈΪ9.76m/s2£¬Ð¡×éͬѧÓÖͨ¹ý²éÔÄ×ÊÁÏÖªµÀµ±µØµÄÖØÁ¦¼ÓËÙ¶È
Ϊ9.78m/s2£¬Ôò£¬´ÓAµ½BµÄ¹ý³ÌÖУ»¼õСµÄÖØÁ¦ÊÆÄÜΪ0.314m£®

·ÖÎö ¸ù¾ÝÊúÖ±·½Ïò¡÷x=gT2£¬ÇóµÃʱ¼äT£¬ÔÚÀûÓÃˮƽ·½ÏòÉÏ×öÔÈËÙÖ±ÏßÔ˶¯£¬½áºÏË®Æ½Î»ÒÆºÍʱ¼ä¼ä¸ôÇó³ö³õËٶȵĴóС£»
¸ù¾Ý¶¯Äܵıí´ïʽ£¬´Ó¶øÇóµÃ¶¯ÄܵÄÔöÁ¿£¬ÔÙÔËÓÃÖØÁ¦ÊÆÄܱí´ïʽEP=mgh£¬´Ó¶ø¼´¿ÉÇó½â£®

½â´ð ½â£º£¨1£©ÓÉÆ½Å×Ô˶¯µÄÊúÖ±·½ÏòÔ˶¯¹æÂɿɵ㬡÷x=gT2£¬
½âµÃʱ¼äT=$\sqrt{\frac{0.025-0.016-£¨0.016-0.009£©}{9.8}}$=0.0143s£¬
СÇòµÄ³õËÙ¶Èv0=$\frac{s}{2T}$=$\frac{0.0149-0.0043}{2¡Á0.0143}$m/s=0.371m/s£®
£¨2£©¸ù¾Ý¶¯Äܱí´ïʽ£¬ÔòÓж¯ÄܵÄÔöÁ¿£º¡÷EK=$\frac{1}{2}$m${v}_{B}^{2}$-$\frac{1}{2}$m${v}_{A}^{2}$=$\frac{1}{2}$m£¨${v}_{By}^{2}$-${v}_{Ay}^{2}$£©£¬
ͨ¹ý²éÔÄ×ÊÁÏÖªµÀµ±µØµÄÖØÁ¦¼ÓËÙ¶ÈΪ9.78m/s2£¬
Ôò´ÓAµ½BµÄ¹ý³ÌÖУ»¼õСµÄÖØÁ¦ÊÆÄÜΪ¡÷EP=m¡Á9.78¡Á£¨0.036-0.004£©=0.314m
¹Ê´ð°¸Îª£º£¨1£©0.371£»£¨2£©$\frac{1}{2}$m£¨${v}_{By}^{2}$-${v}_{Ay}^{2}$£©£¬0.314m£®

µãÆÀ ¿¼²éƽÅ×Ô˶¯µÄ¹æÂÉ£¬ÕÆÎÕÔ˶¯Ñ§¹«Ê½µÄÄÚÈÝ£¬×¢ÒâÇóµÃ³õËٶȵķ½·¨£¬Àí½â¶¯ÄܵÄÔöÁ¿£¬¼°ÖØÁ¦ÊÆÄܵıí´ïʽÖÐÖØÁ¦¼ÓËٶȵÄȡֵ£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
14£®ÔÚ¡°Ñо¿ÔȱäËÙÖ±ÏßÔ˶¯¡±µÄʵÑéÖУº
£¨1£©Ä¿Ç°ÊµÑéÊÒÓõĴòµã¼ÆÊ±Æ÷Óеç´Å´òµã¼ÆÊ±Æ÷ºÍµç»ð»¨´òµã¼ÆÊ±Æ÷Á½ÖÖ£¬ËüÃǵÄÔ­Àí»ù±¾Ò»Ñù£¬Ëù½ÓµçÔ´¾ùΪƵÂÊΪ50HzµÄ½»Á÷µçÔ´£¬Ã¿¸ô0.02s´òÒ»´Îµã£®
£¨2£©³ý´òµã¼ÆÊ±Æ÷£¨º¬Ö½´ø¡¢¸´Ð´Ö½£©¡¢Ìú¼Ų̈£¨º¬Ìú¼Ð£©Í⣬ÔÚÏÂÃæµÄÒÇÆ÷ºÍÆ÷²ÄÖУ¬»¹±ØÐëʹÓõÄÓÐAD£¨ÌîÑ¡Ïî´úºÅ£©
A£®µçѹºÏÊʵÄ50Hz½»Á÷µçÔ´          B£®µçѹ¿Éµ÷µÄÖ±Á÷µçÔ´
C£®Ãë±í         D£®¿Ì¶È³ß           E£®ÖØ´¸
£¨3£©ÊµÑé¹ý³ÌÖУ¬Îª¼õС²âÁ¿ÖØÁ¦×÷ÓÃÏÂÖ½´ø¼ÓËٶȵÄÎó²î£¬ÏÂÁдëÊ©ÖÐÓÐÒæµÄÊÇCD
A£®Ñ¡ÔñÖÊÁ¿½ÏСµÄÖØ´¸
B£®Ê¹Ö½´øÔ˶¯¼ÓËٶȾ¡Á¿Ð¡Ò»Ð©
C£®ÔÚÏàͬµÄÌõ¼þÏ£¬´ò³ö¶àÌõÖ½´ø£¬Ñ¡ÆäÖÐÒ»Ìõ×îÀíÏëµÄ½øÐвâÁ¿ºÍ¼ÆËã
D£®ÉáÈ¥Ö½´øÉϽÏÃܼ¯µÄµã£¬È»ºóѡȡ¼ÆÊýµã£¬½øÐмÆËã
£¨4£©ÔڲⶨÔȱäËÙÖ±ÏßÔ˶¯¼ÓËÙ¶ÈʵÑéÖУ¬Ä³´ÎʵÑéÖ½´øµÄ¼Ç¼ÈçͼËùʾ£¬Èôÿ´ò5¸öµãȡһ¸ö¼ÇÊýµã£¬·Ö±ð±êÃ÷0¡¢1¡¢2¡¢3¡¢4£¬¼ÇÊýµã¼äµÄʱ¼ä¼ä¸ô¼ÇΪT£®Á¿µÃx1=30.0mm£¬x2=36.0mm£¬x3=42.0mm£¬x4=48.0mm£¬Ôò´òÓ¡µã2ʱֽ´øµÄ˲ʱËÙ¶Èv2µÄ±í´ïʽv2=$\frac{{x}_{2}+{x}_{3}}{2T}$£¬´úÈëÊý¾Ýv2=0.39m/s£»ÎïÌåµÄ¼ÓËÙ¶ÈaµÄ±í´ïʽa=$\frac{£¨{x}_{3}+{x}_{4}£©-£¨{x}_{1}+{x}_{2}£©}{4{T}^{2}}$£¬´úÈëÊý¾Ýa=0.60m/s2£®£¨½á¹û±£ÁôÁ½Î»ÓÐЧÊý×Ö£©
8£®Èçͼ1µÍ¿ÕÌøÉ¡ÊÇÒ»ÖÖ¼«ÏÞÔ˶¯£¬Ò»°ãÔÚ¸ßÂ¥¡¢ÐüÑ¡¢¸ßËþµÈ¹Ì¶¨ÎïÉÏÆðÌø£®ÈËÔÚ¿ÕÖнµÂä¹ý³ÌÖÐËùÊÜ¿ÕÆø×èÁ¦ËæÏÂÂäËٶȵÄÔö´ó¶øÔö´ó£¬¶øÇÒËÙ¶ÈÔ½´ó¿ÕÆø×èÁ¦Ôö´óµÃÔ½¿ì£®ÒòµÍ¿ÕÌøÉ¡ÏÂÂäµÄ¸ß¶ÈÓÐÏÞ£¬µ¼ÖÂÔÚ¿ÕÖе÷Õû×Ë̬¡¢´ò¿ªÉ¡°üµÄʱ¼ä½Ï¶Ì£¬ËùÒÔÆäΣÏÕÐԱȸ߿ÕÌøÉ¡»¹Òª¸ß£®
Ò»ÃûÖÊÁ¿Îª70kgµÄÌøÉ¡Ô˶¯Ô±±³ÓÐÖÊÁ¿Îª10kgµÄÉ¡°ü´Óij¸ß²ã½¨Öþ¶¥²ãÌøÏ£¬ÇÒÒ»Ö±ÑØÊúÖ±·½ÏòÏÂÂ䣬ÆäÕû¸öÔ˶¯¹ý³ÌµÄv-tͼÏóÈçͼ2Ëùʾ£®ÒÑÖª2.0sÄ©µÄËÙ¶ÈΪ18m/s£¬10sÄ©À­¿ªÉþË÷¿ªÆô½µÂäÉ¡£¬16.2sʱ°²È«Â䵨£¬²¢ÎÈÎȵØÕ¾Á¢ÔÚµØÃæÉÏ£®gÈ¡10m/s2£¬Çë¸ù¾Ý´ËͼÏó¹ÀË㣺
£¨1£©ÆðÌøºó2sÄÚÔ˶¯Ô±£¨°üÀ¨ÆäËæÉíЯ´øµÄÈ«²¿×°±¸£©ËùÊÜÆ½¾ù×èÁ¦µÄ´óС£»
£¨2£©Ô˶¯Ô±´Ó½Å´¥µØµ½×îºóËٶȼõΪÁãµÄ¹ý³ÌÖУ¬Èô²»¼ÆÉ¡µÄÖÊÁ¿¼°´Ë¹ý³ÌÖÐµÄ¿ÕÆø×èÁ¦£¬ÔòÔ˶¯Ô±ËùÐè³ÐÊܵØÃæµÄƽ¾ù³å»÷Á¦¶à´ó£»
£¨3£©¿ªÉ¡Ç°¿ÕÆø×èÁ¦¶ÔÌøÉ¡Ô˶¯Ô±£¨°üÀ¨ÆäËæÉíЯ´øµÄÈ«²¿×°±¸£©Ëù×öµÄ¹¦£¨½á¹û±£ÁôÈýλÓÐЧÊý×Ö£©£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø