题目内容


如图,带电荷量为+q、质量为m的滑块,沿固定的绝缘斜面匀速下滑。现加上一竖直向上的匀强电场,电场强度为E,且qEmg。物体沿斜面下滑的过程中,以下说法正确的是

A.滑块将沿斜面减速下滑

B.滑块仍沿斜面匀速下滑

C.加电场前,系统机械能守恒

D.加电场后,重力势能的减少量大于电势能的增加量

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以下是“描绘小灯泡的伏安特性曲线”实验的操作步骤:                                               

A.闭合电键,记下电流表、电压表的一组示数(I,U),移动变阻器的滑动触头位置,每移动一次记下一组(I,U)值,共测出12组左右的数据.                                                                                          

B.将电流表、电压表、变阻器、电灯、电源开关正确连成电路,电流表外接,变阻器采用分压式,如图所示                                                                                                                                        

C.调节触头位置,使闭合电键前触头处于变阻器的左端.                                        

D.按所测数据,在坐标纸上描点并将各点用直线段连结起来,得出小灯泡的伏安特性曲线.                                                                                                                                         

(1)以上各步骤中存在错误或不妥之处的是                                            ,应如何改正                 ?                        

(2)将步骤纠正后,按实验先后顺序排列起来                          .                             

                                                                                                         

                                                                                                                                  


某同学用如图所示的装置测定重力加速度.                                                              

①打出的纸带如图所示,实验时纸带的                                                  端通过夹子和重物相连接.(选填“甲”或“乙”)                                                                                                                

②纸带上1至9各点为计时点,由纸带所示数据可算出实验时的重力加速度为         m/s2.(已知交流电频率为50Hz)                                                                                                            

③若当地的重力加速度数值为9.8m/s2,请列出测量值与当地重力加速度的值有差异的一个原因  .                 

                                                                                                                         

                                                                                                                                 

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