ÌâÄ¿ÄÚÈÝ
ÈçͼËùʾ£¬ÔÚË®Æ½ÃæÉÏ·ÅÖÃÒ»°¼²ÛB£¬BÓëË®Æ½ÃæÃæ¼äÓÐĦ²Á£¬²ÛÖÊÁ¿Îªm,ÄÚ±Ú¼ä¾àÀëΪd£¬²ÛÄÚ¿¿½ü×ó²à±Ú´¦ÓÐÖÊÁ¿Ò²ÎªmСÎï¿éA£¬´øÓÐqµçÁ¿Õýµç£¬²ÛÄÚ±Ú¾øÔµ¹â»¬£¬ÏµÍ³ÓÖ´¦ÓÚһˮƽÏòÓÒµÄÔÈÇ¿µç³¡ÖУ¬µç³¡Ç¿¶ÈΪE£¬t=0ʱ¿ÌAÓɾ²Ö¹ÊÍ·Å£¬Ã¿´ÎAÓë²ÛBÄÚ±ÚÅöײÎÞ¶¯ÄÜËðʧ½»»»ËÙ¶È¡£¹Û²ì·¢ÏÖAÖ»Óë²ÛBÓÒ±Ú·¢ÉúÖÜÆÚÐÔµÄÅöײ£¬ÇÒÿ´ÎÅöºóËÙ¶ÈΪÁã¡£Çó
£¨1£©AµÚÒ»´ÎÓë²ÛB·¢ÉúÅöײǰµÄËÙ¶È
£¨2£©²ÛBÓëË®Æ½Ãæ¼ä¶¯Ä¦²ÁÒòÊý¦Ì
£¨3£©ÒÔºóÔ˶¯¹ý³ÌÖÐAÓë²ÛB×ó±ÚµÄ×î¶Ì¾àÀëºÍµÚn´ÎÅöײǰĦ²ÁÁ¦¶Ô²ÛBËù×ö¹¦
£¨1£©AÅöǰËÙ¶Èv0, Óɶ¯Äܶ¨Àí
£¨2·Ö£©
£¨2·Ö£©
(2)¸ù¾ÝÌâÒ⣬±£Ö¤ÖÜÆÚÐÔÅö£¬Ã¿´ÎA¼ÓËÙÖÁv0,ʱ£¬B¸ÕºÃËٶȼõµ½Á㣬¶øAµ½´ïBÓÒ±Ú
ËùÒÔAB¼ÓËÙ¶È´óСÏàµÈ aA=qE/m aB=2¦Ìmg/m £¨2·Ö£©
2¦Ìmg=qE £¨2·Ö£©
µÃ ¦Ì=qE/2mg £¨2·Ö£©
(3)ÿ´Îµ±A¼ÓËÙµ½v0/2¶øB¼õËÙµ½v0/2ʱ£¬AÀë×ó±Ú×î½ü£¬ÉèÖÜÆÚTΪ
£¨2·Ö£©
AÏà¶ÔBÓÒ±Ú x=3v0/4¡ÁT/2- v0 /4¡ÁT/2=d/2 £¨2·Ö£©
µÚn´ÎÅöǰ£¬BÔ˶¯£¨n-1£©d
Wf=-2¦Ìmg(n-1)d=-(n-1)qEd £¨3·Ö£©