ÌâÄ¿ÄÚÈÝ

3£®ÈçͼËùʾ£¬t=0ʱ£¬ÖÊÁ¿Îª0.5kgÎïÌå´Ó¹â»¬Ð±ÃæÉϵÄAµãÓɾ²Ö¹¿ªÊ¼Ï»¬£¬¾­¹ýBµãºó½øÈëË®Æ½Ãæ£¨Éè¾­¹ýBµãǰºóËÙ¶È´óС²»±ä£©£¬×îºóÍ£ÔÚCµã£®²âµÃÿ¸ô2sµÄÈý¸öʱ¿ÌÎïÌåµÄ˲ʱËٶȼǼÔÚϱíÖУ¬ÓÉ´Ë¿ÉÖª£¨ÖØÁ¦¼ÓËÙ¶Èg=10m/s2£©£¨¡¡¡¡£©
t/s0246
v/£¨m•s-1£©08128
A£®ÎïÌåÔ˶¯¹ý³ÌÖеÄ×î´óËÙ¶ÈΪ$\frac{40}{3}$m/s£®
B£®t=3sµÄʱ¿ÌÎïÌåÇ¡ºÃ¾­¹ýBµã
C£®t=10sµÄʱ¿ÌÎïÌåÇ¡ºÃÍ£ÔÚCµã
D£®BC²¿·ÖµÄ¶¯Ä¦²ÁÒòÊýΪ0.2

·ÖÎö ¸ù¾Ýͼ±íÖеÄÊý¾Ý£¬ÓÉÔ˶¯Ñ§¹«Ê½¿ÉÒÔÇó³öÎïÌåÏ»¬µÄ¼ÓËÙ¶Èa1=4m/s2ºÍÔÚË®Æ½ÃæÉϵļÓËÙ¶Èa2=-2m/s2£®Èç¹ûµÚ4s»¹ÔÚÐ±ÃæÉϵϰ£¬ËÙ¶ÈӦΪ16m/s£¬´Ó¶øÅжϳöµÚ4sÒѹýBµã£®Í¨¹ýÔ˶¯Ñ§¹«Ê½Çó³övB£¬¼´¿ÉÇó³öAB¡¢BCµÄ¾àÀ룮

½â´ð ½â£ºAB¡¢¸ù¾Ýͼ±íÖеÄÊý¾Ý£¬¿ÉÒÔÇó³öÎïÌåÏ»¬µÄ¼ÓËÙ¶Èa1=4m/s2ºÍÔÚË®Æ½ÃæÉϵļÓËÙ¶Èa2=-2m/s2£®
¸ù¾ÝÔ˶¯Ñ§¹«Ê½£º8+a1t1-a2t2=12£¬t1+t2=2£¬
½â³öt1=$\frac{40}{3}$s£¬Öª¾­¹ý$\frac{10}{3}$sµ½´ïBµã£¬µ½´ïBµãʱµÄËÙ¶Èv=a1t=$\frac{40}{3}$m/s£®
Èç¹ûµÚ4s»¹ÔÚÐ±ÃæÉϵϰ£¬ËÙ¶ÈӦΪ16m/s£¬´Ó¶øÅжϳöµÚ4sÒѹýBµã£®ÊÇÔÚ2sµ½4sÖ®¼ä¾­¹ýBµã£®ËùÒÔ×î´óËٶȲ»ÊÇ12m/s£®¹ÊAÕýÈ·£¬B´íÎó£®
C¡¢µÚ6sÄ©µÄËÙ¶ÈÊÇ8m/s£¬µ½Í£ÏÂÀ´»¹ÐèµÄʱ¼ät¡ä=$\frac{0-8}{-2}$s=4s£¬ËùÒÔµ½CµãµÄʱ¼äΪ10s£®¹ÊCÕýÈ·£®
D¡¢¸ù¾Ýv2-v02=2ax£¬Çó³öAB¶ÎµÄ³¤¶ÈΪ$\frac{200}{9}$m£®BC¶Î³¤¶ÈΪ$\frac{400}{9}$m£¬ÔòA¡¢B¼äµÄ¾àÀëСÓÚB¡¢C¼äµÄ¾àÀ룬¹ÊDÕýÈ·£®
¹ÊÑ¡£ºACD

µãÆÀ ½â¾ö±¾ÌâµÄ¹Ø¼üÊìÁ·ÕÆÎÕÔ˶¯Ñ§¹«Ê½v2-v02=2ax¡¢v=v0+at£¬²¢ÄÜͨ¹ý¼ÆËã·ÖÎöÎïÌåµÄÔ˶¯¹ý³Ì£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø