ÌâÄ¿ÄÚÈÝ

19£®ÈçͼËùʾ£¬Ë®Æ½µØÃæÉÏ¿ÕÓÐÒ»¼Ü·É»úÔÚ½øÐÐͶµ¯ÑµÁ·£¬·É»úÑØË®Æ½·½Ïò×öÔȼÓËÙÖ±ÏßÔ˶¯£®µ±·É»ú·É¾­¹Û²ìµãBµÄÕýÉÏ·½AµãʱÊÍ·ÅÒ»¿ÅÕ¨µ¯£¬¾­Ê±¼äTÕ¨µ¯ÂäÔÚ¹Û²ìµãBÕýǰ·½L´¦µÄCµã£»ÔÚµÚÒ»¿ÅÕ¨µ¯Â䵨µÄͬʱÊͷŵڶþ¿ÅÕ¨µ¯£¬µÚ¶þ¿ÅÕ¨µ¯ÂäÔÚ¹Û²ìµãBÕýǰ·½µÄDµã£¬²âµÃBD=3L£¬²»¼Æ¿ÕÆø×èÁ¦£¬Çó£º
£¨1£©·É»úÊͷŵÚÒ»¿ÅÕ¨µ¯Ê±µÄËÙ¶ÈvA£»
£¨2£©·É»úˮƽ·ÉÐеļÓËÙ¶Èa£®

·ÖÎö £¨1£©ÓÉÌâÒâ¿ÉÖеÚÒ»´ÎͶµ¯Ê±µÄË®Æ½Î»ÒÆ£¬¸ù¾Ý·É»úµÄÔ˶¯¿ÉÖªµÚ¶þ´ÎͶµ¯Ê±·É»úǰ½øµÄ¾àÀ룬ÔòÓÉÆ½Å×Ô˶¯µÄ¹æÂÉ¿ÉÇóµÃÁ½´ÎͶµ¯Ê±·É»úµÄËÙ¶È£»
£¨2£©¸ù¾ÝÎ»ÒÆÊ±¼ä¹«Ê½¡¢ËÙ¶Èʱ¼ä¹«Ê½£¬½áºÏÎ»ÒÆ¹ØÏµÇó³ö¼ÓËٶȵĴóС£»

½â´ð ½â£º£¨1£©Éè·É»úˮƽ·ÉÐеļÓËÙ¶ÈΪa£¬ÊͷŵÚÒ»¿ÅÕ¨µ¯Ê±µÄËÙ¶ÈΪvA£¬·É»úÔÚTʱ¼äÄÚµÄÎ»ÒÆÎªs£¬Êͷŵڶþ¿ÅÕ¨µ¯Ê±µÄËÙ¶ÈΪv£¬
ÓУºL=vAT£¬
½âµÃ${v}_{A}=\frac{L}{T}$£®
£¨2£©¸ù¾Ý$s={v}_{A}T+\frac{1}{2}a{T}^{2}$£¬v=vA+aT£¬
BD=s+vT£¬
ÓÉÓÚBD=3L£¬
ÁªÁ¢½âµÃa=$\frac{2L}{3{T}^{2}}$£®
´ð£º£¨1£©·É»úÊͷŵÚÒ»¿ÅÕ¨µ¯Ê±µÄËÙ¶ÈΪ$\frac{L}{T}$£»
£¨2£©·É»úˮƽ·ÉÐеļÓËÙ¶ÈΪ$\frac{2L}{3{T}^{2}}$£®

µãÆÀ ±¾ÌâÒªÌØ±ð×¢Òâ·É»úµÄÔ˶¯£¬Òò·É»úΪÔȱäËÙÔ˶¯£¬¹ÊÁ½´ÎÅ׳öʱµÄËٶȲ»Í¬£¬µ«ÎïÌåµÄËÙ¶ÈÓëÅ׳öʱ·É»úµÄËÙ¶ÈÏàͬ£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø