ÌâÄ¿ÄÚÈÝ
ÈçͼËùʾ¡£Õý·½ÐÎÇøÓòabcd±ß³¤L=(1)Á£×Ó´©¹ý½çÃæPSʱƫÀëÖÐÐÄÏßORµÄ¾àÀëy£»
(2)Á£×Ó´©¹ý½çÃæPSʱµÄËÙ¶È´óСÓë·½Ïò£»
(3)OµãÓëPSÃæµÄ¾àÀëx£»
(4)µãµçºÉQµÄµçÐÔ¼°µçÁ¿´óС¡£
![]()
(1)Éè´øµçÁ£×ÓÀ뿪ÔÈÇ¿µç³¡Ê±ÔÚÊúÖ±·½Ïò·¢ÉúµÄÎ»ÒÆy1
![]()
y1=
at2=![]()
=0.
Óɼ¸ºÎ֪ʶ¿ÉÖª
![]()
µÃ£ºy=12 cm
(2)Éè´øµçÁ£×ÓÀ뿪ÔÈÇ¿µç³¡Ê±ÔÚÊúÖ±·½ÏòµÄ·ÖËÙ¶ÈΪvy
vy=at=![]()
=1.5¡Á
Á£×Ó´©¹ý½çÃæPSʱµÄËÙ¶È´óСvµÈÓÚÁ£×ÓÀ뿪ÔÈÇ¿µç³¡Ê±µÄËÙ¶È´óС
¼´£ºv=![]()
=2.5¡Á
tan ¦È=vy/v0=1.5¡Á106£¯2¡Á106=3£¯4
¦È=37¡ã
¼´ÎªÁ£×Ó´©¹ý½çÃæPSʱÓëˮƽ·½ÏòµÄ¼Ð½Ç
(3)tan ¦È=x£¯y
x=ytan ¦È=12¡Á3£¯4=9 cm
(
r=
=15 cm
Á£×ÓÓÉ¿âÂØÁ¦ÌṩÏòÐÄÁ¦£¬ÔòÓÐ
![]()
¡àQ=![]()
¡Ö1.04¡Á10-8 C
QΪ¸ºµçºÉ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
| A¡¢Á£×Ó½«´ÓaµãÉä³ö´Å³¡ | B¡¢Á£×Ó½«´ÓbÉä³ö´Å³¡ | C¡¢Á£×ÓÔڴų¡ÖÐÔ˶¯µÄʱ¼äÏàͬ | D¡¢Á£×ÓÔڴų¡ÖÐÔ˶¯µÄʱ¼ä²»Í¬ |