ÌâÄ¿ÄÚÈÝ

£¨2013ɽ¶«Ê¡µÂÖÝÊп¼Ç°ÑµÁ·Ìâ5£©ÈçͼËùʾ£¬Ë®Æ½·ÅÖõÄÔ²ÅÌÉÏ£¬ÔÚÆä±ßÔµ C µã¹Ì¶¨Ò»¸öСͰ£¬Í°µÄ¸ß¶È²»¼Æ£¬Ô²Å̰뾶Ϊ R = 1 m,ÔÚÔ²ÅÌÖ±¾¶ CD µÄÕýÉÏ·½£¬Óë CD ƽÐзÅÖÃÒ»Ìõˮƽ»¬µÀ AB £¬»¬µÀÓÒ¶Ë B ÓëÔ²ÅÌÔ²ÐÄ O ÔÚͬһÊúÖ±ÏßÉÏ£¬ÇÒ B µã¾àÀëÔ²ÅÌÔ²ÐĵÄÊúÖ±¸ß¶È h = 1£®25 m£¬ÔÚ»¬µÀ×ó¶Ë¾²Ö¹·ÅÖÃÖÊÁ¿Îª m = 0£®4 kgµÄÎï¿é£¨¿ÉÊÓΪÖʵ㣩£¬Îï¿éÓ뻬µÀµÄ¶¯Ä¦²ÁÒòÊýΪ ¦Ì = 0£®2£¬ÏÖÓÃÁ¦ F = 4 NµÄˮƽ×÷ÓÃÁ¦À­¶¯Îï¿é£¬Í¬Ê±Ô²ÅÌ´ÓͼʾλÖã¬ÒÔ½ÇËÙ¶È ¦Ø = 2¦Ð  rad/s£¬ÈÆÍ¨¹ýÔ²ÐÄ O µÄÊúÖ±ÖáÔÈËÙת¶¯£¬À­Á¦×÷ÓÃÔÚÎï¿éÒ»¶Îʱ¼äºó³·µô£¬×îÖÕÎï¿éÓÉB µãˮƽÅ׳ö£¬Ç¡ºÃÂäÈëÔ²Å̱ßÔµµÄСͰÄÚ£®ÖØÁ¦¼ÓËÙ¶ÈÈ¡10m/s2£®

£¨1£©ÈôÀ­Á¦×÷ÓÃʱ¼äΪ0£®5s£¬ÇóËùÐ軬µÀµÄ³¤¶È£»

£¨2£©ÇóÀ­Á¦×÷ÓõÄ×î¶Ìʱ¼ä£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø