ÌâÄ¿ÄÚÈÝ

°ÑÁ½¸ö´óСÏàͬ¡¢ÖÊÁ¿²»µÈµÄ½ðÊôÇòÓÃϸÏßÁ¬½Ó£¬Öмä¼ÐÒ»±»Ñ¹ËõÁ˵ÄÇᵯ»É£¬ÖÃÓÚĦ²Á¿ÉÒÔ²»¼ÆµÄˮƽ×ÀÃæÉÏ£¬ÈçͼËùʾ£®ÏÖÉÕ¶ÏϸÏߣ¬¹Û²ìÁ½ÇòµÄÔ˶¯Çé¿ö£¬½øÐбØÒªµÄ²âÁ¿£¬ÑéÖ¤ÎïÌå¼äÏ໥×÷ÓÃʱ¶¯Á¿Êغ㣮

     £¨1£©³ýľ°å¡¢°×Ö½¡¢¸´Ð´Ö½¡¢Í¼¶¤Íâ

»¹±ØÐèµÄÆ÷²ÄÊÇ__________£¨Ìî×Öĸ´úºÅ£©

AÌìÆ½¡¡ B¿Ì¶È³ß¡¡ CǦ´¸¡¡ DÃë±í  Hµ¯»É²âÁ¦¼Æ

     £¨2£©ÐèÖ±½Ó²âÁ¿µÄÊý¾ÝÊÇ______________________

     £¨3£©ÓÃËùµÃÊý¾ÝÑéÖ¤¶¯Á¿Êغ㶨ÂɵĹØÏµÊ½ÊÇ________________

 

¡¾´ð°¸¡¿

£¨1£©A¡¢B¡¢C

£¨2£©Á½Ð¡ÇòµÄÖÊÁ¿m1. m2¼°ËüÃǶÔÓ¦µÄƽÅ×Éä³ÌS1. S2

£¨3£©m1S1=m2S2£¨ÔÚÎó²îÔÊÐíµÄ·¶Î§ÄÚ£©

¡¾½âÎö¡¿ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨I£© °ÑÁ½¸ö´óСÏàͬ¡¢ÖÊÁ¿²»µÈµÄ½ðÊôÇòÓÃϸÏßÁ¬½Ó£¬Öмä¼ÐÒ»±»Ñ¹ËõÁ˵ÄÇáÖʶ̵¯»É£¬ÖÃÓÚĦ²Á¿ÉÒÔ²»¼ÆµÄˮƽ×ÀÃæÉÏ£¬ÈçͼËùʾ£®ÏÖÉÕ¶ÏϸÏߣ¬¹Û²ìÁ½ÇòµÄÔ˶¯Çé¿ö£¬½øÐбØÒªµÄ²âÁ¿£¬ÑéÖ¤ÎïÌå¼äÏ໥×÷ÓÃʱ¶¯Á¿Êغ㣮

£¨1£©ÎªÍê³ÉʵÑ飬ÒѾ­×¼±¸ÁËÁ½¸ö½ðÊôÇò¡¢µ¯»É¡¢Ï¸Ïß¡¢Í¼¶¤¡¢¸´Ð´Ö½¡¢°×Ö½¡¢Ä¾°å¡¢Ç¦´¸£¬»¹±ØÐëÌí¼ÓµÄÆ÷²ÄÊÇ
ÌìÆ½¡¢¿Ì¶È³ß
ÌìÆ½¡¢¿Ì¶È³ß
£®
£¨2£©ÐèÖ±½Ó²âÁ¿µÄÊý¾ÝÊÇ
Á½Ð¡ÇòµÄÖÊÁ¿m1ºÍm2£¬Á½Ð¡ÇòÂ䵨µãµ½×ÀÃæ±ßÔµµÄˮƽ¾àÀëS1£¬S2
Á½Ð¡ÇòµÄÖÊÁ¿m1ºÍm2£¬Á½Ð¡ÇòÂ䵨µãµ½×ÀÃæ±ßÔµµÄˮƽ¾àÀëS1£¬S2
£®
£¨3£©ÓÃËùµÃÊý¾ÝÑéÖ¤¶¯Á¿Êغ㶨ÂɵĹØÏµÊ½ÊÇ
m1S1=m2S2
m1S1=m2S2
£®
£¨II£©ÔÚÀûÓÃ×ÔÓÉÂäÌåÔ˶¯ÑéÖ¤»úеÄÜÊØºã¶¨ÂɵÄʵÑéÖУ¬µçÔ´µÄƵÂÊΪf£¬ÒÀ´Î´ò³öµÄµãΪ0£¬1£¬2£¬3£¬4£¬¡­n£®µ±µØÖØÁ¦¼ÓËÙ¶ÈΪg£®Ôò£º
£¨4£©ÈçÓõÚ2µãµ½µÚ6µãÖ®¼äµÄÖ½´øÀ´ÑéÖ¤£¬ÏÖÒѲâÁ¿³öµÄÎïÀíÁ¿Îª£ºÖØ´¸µÄÖÊÁ¿Îªm£¬µÚ2µãµ½µÚ6µãÖ®¼äµÄ¾àÀëh26£»µÚ1µãµ½µÚ3µãÖ®¼äµÄ¾àÀëh13£»µÚ5µãµ½µÚ7µãÖ®¼äµÄ¾àÀëh57£»¼õÉÙµÄÖØÁ¦ÊÆÄÜΪ¡÷¦¥¦±=
mgh26
mgh26
£¬¶¯ÄܵÄÔöÁ¿Îª¡÷¦¥k=
1
8
mf2(
h
2
57
-
h
2
13
)
1
8
mf2(
h
2
57
-
h
2
13
)
£®
£¨5£©ÏÂÁÐʵÑé²½Öè²Ù×÷ºÏÀíµÄ˳ÐòÅÅÁÐÊÇ
ADBCEF
ADBCEF
£¨Ìîд²½ÖèÇ°ÃæµÄ×Öĸ£©£®
A£®½«´òµã¼ÆÊ±Æ÷ÊúÖ±°²×°ÔÚÌú¼Ų̈ÉÏ
B£®½ÓͨµçÔ´£¬ÔÙËÉ¿ªÖ½´ø£¬ÈÃÖØÎï×ÔÓÉÏÂÂä
C£®È¡ÏÂÖ½´ø£¬¸ü»»ÐÂÖ½´ø£¨»ò½«Ö½´ø·­¸öÃæ£©ÖØÐÂ×öʵÑé
D£®½«ÖØÎï¹Ì¶¨ÔÚÖ½´øµÄÒ»¶Ë£¬ÈÃÖ½´ø´©¹ý´òµã¼ÆÊ±Æ÷£¬ÓÃÊÖÌá×ÅÖ½´ø
E£®Ñ¡ÔñÒ»ÌõÖ½´ø£¬Óÿ̶ȳ߲â³öÎïÌåÏÂÂäµÄ¸ß¶Èh1£¬h2£¬h3¡­£¬hn£¬¼ÆËã³ö¶ÔÓ¦µÄ˲ʱËÙ¶Èv1£¬v2£¬v3£¬¡­vn
F£®·Ö±ðËã³ö
1
2
m
v
2
n
ºÍmghn£¬ÔÚʵÑéÎó²î·¶Î§ÄÚ¿´ÊÇ·ñÏàµÈ£®
¾«Ó¢¼Ò½ÌÍøÊµÑéÌâ
£¨¢ñ£©°ÑÁ½¸ö´óСÏàͬ¡¢ÖÊÁ¿²»µÈµÄ½ðÊôÇòÓÃϸÏßÁ¬½Ó£¬Öмä¼ÐÒ»±»Ñ¹ËõÁ˵ÄÇᵯ»É£¬ÖÃÓڹ⻬µÄˮƽ×ÀÃæÉÏ£¬ÈçͼËùʾ£®ÉÕ¶ÏϸÏߣ¬¹Û²ìÁ½ÇòµÄÔ˶¯Çé¿ö£¬½øÐбØÒªµÄ²âÁ¿£¬Ñо¿ÎïÌå¼äÏ໥×÷ÓÃʱµÄÊØºãÁ¿£º
£¨1£©ÊµÑéÆ÷²Ä³ýÁËÁ½¸ö½ðÊôÇò¡¢Çᵯ»É¡¢Ï¸Ïß¡¢ÖØ´¸Ïß¡¢°×Ö½¡¢¸´Ð´Ö½Í⣬»¹ÒªÓУº
 

£¨2£©ÐèÒªÖ±½Ó²âÁ¿µÄÊý¾ÝÊÇ£º
 

£¨3£©¸ù¾ÝʵÑéÊý¾Ý¿ÉÒÔÍÆ²âʵÑéÖеÄÊØºãÁ¿ÊÇ£º
 
£¨A¶¯ÄÜEk=
1
2
mv2
£¬B¶¯Á¿p=mv£¬CËÙ¶È£©
£¨¢ò£©Ä³Í¬Ñ§´ÓС··ÄÇÀïµÍ¼ÛÂòÁËÒ»¸öÊÖ»ú£¬ÏÈÓûͨ¹ý¶ÔÊÖ»úµç³Ø£¨Èçͼ£©µÄµç¶¯ÊƺÍÄÚ×èµÄ²âÊÔÀ´ÅжÏÊÖ»úµÄÐÔÄÜ£¬ÇëÀûÓÃѧ¹ýµÄ֪ʶ°ïËûÉè¼ÆÕâ¸öʵÑ飮¿É¹©Ñ¡ÔñµÄÆ÷²Ä¼û±íËùÁУ¬¸ÃͬѧµÄǰÆÚ¹¤×÷ÈçÏ£º
¾«Ó¢¼Ò½ÌÍø
µçÁ÷±íA£¨0.6A£¬3A  r=2¦¸£©
µçѹ±íV1£¨3V£¬15V   r=1000¦¸£©
»¬¶¯±ä×èÆ÷R1£¨0¡«10¦¸  1A£©
»¬¶¯±ä×èÆ÷R2£¨0¡«1000¦¸  200mA£©
´ý²âµç³Ø
µç¼ü¡¢µ¼ÏßÈô¸É£®
1Çë¸ù¾ÝÏÖÓÐÆ÷²ÄÉè¼Æµç·ͼ£¬ÆäÖ묶¯±ä×èÆ÷ӦѡÔò
 
£®
¾«Ó¢¼Ò½ÌÍø
¢Ú¸ù¾ÝÄãÉè¼ÆµÄµç·ͼ£¬Íê³ÉʵÎïµç·µÄÁ¬½Ó£¨×¢ÒâÁ¿³ÌµÄÑ¡Ôñ£©
£¨×¢£ºÔ­´´£¬ÏÖÔÚÎÒÊ¡ÊÖ»úµÄÆÕ¼°³Ì¶ÈºÜ¸ß£¬µ«Êг¡ÉϳöÏÖÁ˺ܶàɽկ»ú£¬Í¨¹ý¶Ôµç°åµÄ²âÊÔ£¬ÓÐÖúÓÚÎÒÃÇÅжÏÊÖ»úÐÔÄܵĺûµ£©

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø