若等差数列{an}的前n项和为Sn,且满足
为常数,则称该数列为S数列.
(Ⅰ)判断an=4n-2是否为S数列?并说明理由;
(Ⅱ)若首项为a1的等差数列{an}(an不为常数)为S数列,试求出其通项公式.
0 104595 104603 104609 104613 104619 104621 104625 104631 104633 104639 104645 104649 104651 104655 104661 104663 104669 104673 104675 104679 104681 104685 104687 104689 104690 104691 104693 104694 104695 104697 104699 104703 104705 104709 104711 104715 104721 104723 104729 104733 104735 104739 104745 104751 104753 104759 104763 104765 104771 104775 104781 104789 266669
(Ⅰ)判断an=4n-2是否为S数列?并说明理由;
(Ⅱ)若首项为a1的等差数列{an}(an不为常数)为S数列,试求出其通项公式.