题目内容
若(1＋2x)5＝a0＋a1x＋a2x2＋a3x3＋a4x4＋a5x5，则a0＋a1＋a3＋a5＝
(A) 122 (B) 123 (C) 243 (D) 244
(
B
【解析】略
A．122
B．123
C．243
D．244
若满足2x+=5, 满足2x+2(x－1)=5, +＝
A． B.3 C. D.4
满足2x+
=5, 
满足2x+2
(x－1)=5, 
B.3 C. 
D.4