题目内容
已知{an}为等差数列,则( )A.{logaan}是等差数列 B.{c·an}是等差数列
C.{an·an+1}是等差数列 D.{
}是等差数列
B
解析:设{an}公差为d,则can+1-can=c(an+1-an)=cd.
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题目内容
已知{an}为等差数列,则( )A.{logaan}是等差数列 B.{c·an}是等差数列
C.{an·an+1}是等差数列 D.{
}是等差数列
B
解析:设{an}公差为d,则can+1-can=c(an+1-an)=cd.