题目内容
求下列各式的值:
(1)2lg
-lg
+2lg3+
lg49
(2)(0.027)-
-(-
)-2+(2
)
-(
-1)0.
(1)2lg
| 5 |
| 3 |
| 7 |
| 4 |
| 1 |
| 2 |
(2)(0.027)-
| 1 |
| 3 |
| 1 |
| 7 |
| 7 |
| 9 |
| 1 |
| 2 |
| 2 |
分析:(1)利用对数的性质和运算法则,把2lg
-lg
+2lg3+
lg49等价转化为lg (
×
×9×7),由此能够求出结果.
(2)利用有理数指数幂的性质和运算法则,把(0.027)-
-(-
)-2+(2
)
-(
-1)0等价转化为
-49+
-1,由此能够求出结果.
| 5 |
| 3 |
| 7 |
| 4 |
| 1 |
| 2 |
| 25 |
| 9 |
| 4 |
| 7 |
(2)利用有理数指数幂的性质和运算法则,把(0.027)-
| 1 |
| 3 |
| 1 |
| 7 |
| 7 |
| 9 |
| 1 |
| 2 |
| 2 |
| 1 |
| 0.3 |
| 5 |
| 3 |
解答:解:(1)2lg
-lg
+2lg3+
lg49
=lg (
×
×9×7)
=lg100
=2.
(2)(0.027)-
-(-
)-2+(2
)
-(
-1)0
=
-49+
-1
=-45.
| 5 |
| 3 |
| 7 |
| 4 |
| 1 |
| 2 |
=lg (
| 25 |
| 9 |
| 4 |
| 7 |
=lg100
=2.
(2)(0.027)-
| 1 |
| 3 |
| 1 |
| 7 |
| 7 |
| 9 |
| 1 |
| 2 |
| 2 |
=
| 1 |
| 0.3 |
| 5 |
| 3 |
=-45.
点评:本题考查对数的算性质和有理数指数幂的性质及运算法则,是基础题.解题时要认真审题,仔细解答,注意合理地进行等价转化.
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