题目内容
答案:5x4ax+(lna)x5ax y′=(x5)′ax+x5·(ax)′=5x4ax+x5ax(lna).
函数y=x5ax(a>0且a≠1)的导数是________.
函数y=x5ax(a>0,且a≠1)的导数是
5x4axlna
5x4ax+x5axlna
5x4ax+x5ax
5x4ax+x5axlogae