Question

求下列函数的导数.

(1)y=+sinx;

(2)y=+cosx+3；

(3)y=3x²+xsinx;

(4)y=5x¹⁰sinx-2cosx-9.

Answer 1

解：(1)y′=(+sinx)′=()′+(sinx)′=+cosx.

(2)y′=(+cosx+3)′=()′+(cosx)′+3′=--sinx.

(3)y′=(3x²)′+(xsinx)′=6x+x′sinx+x(sinx)′=6x+sinx+xcosx.

(4)y′=(5x¹⁰sinx)′-(2cosx)′-9′=50x⁹sinx+5x¹⁰cosx-xcosx+2sinx.