题目内容
已知向量a、b满足|
|=1,|
|=2,|
-
|=2,则|
+
|等于( )
| a |
| b |
| a |
| b |
| a |
| b |
| A.1 | B.
| C.
| D.
|
法一:设
=(x1,y1),
=(x2,y2),则x12+y12=1,x22+y22=4,
-
=(x1-x2,y1-y2),
∴(x1-x2)2+(y1-y2)2=4.
∴x12-2x1x2+x22+y12-2y1y2+y22=4.
∴1-2x1x2-2y1y2=0.∴2x1x2+2y1y2=1.
∴(x1+x2)2+(y1+y2)2=1+4+2x1x2+2y1y2=5+1=6.
∴|
+
|=
.
解法二:∵|
+
|2+|
-
|2=2(|
|2+|
|2),
∴|
+
|2=2(|
|2+|
|2)-|
-
|2
=2(1+4)-22=6.
∴|
+
|=
.
故选D
| a |
| b |
| a |
| b |
∴(x1-x2)2+(y1-y2)2=4.
∴x12-2x1x2+x22+y12-2y1y2+y22=4.
∴1-2x1x2-2y1y2=0.∴2x1x2+2y1y2=1.
∴(x1+x2)2+(y1+y2)2=1+4+2x1x2+2y1y2=5+1=6.
∴|
| a |
| b |
| 6 |
解法二:∵|
| a |
| b |
| a |
| b |
| a |
| b |
∴|
| a |
| b |
| a |
| b |
| a |
| b |
=2(1+4)-22=6.
∴|
| a |
| b |
| 6 |
故选D
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