题目内容
设{Sn}是等差数列{an}的前n项和,若
=3,则
=( )
| S8 |
| S4 |
| S16 |
| S8 |
A.
| B.
| C.
| D.3 |
∵
=3,
∴s8=3s4
∴8a1+28d=12a1+18d
∴a1=
d,
∴
=
=
=
故选B.
| S8 |
| S4 |
∴s8=3s4
∴8a1+28d=12a1+18d
∴a1=
| 5 |
| 2 |
∴
| S16 |
| S8 |
| 16a1+120d |
| 8a1+28d |
| 10d |
| 3d |
| 10 |
| 3 |
故选B.
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