题目内容
(本小题满分12分)
△ABC中,A(– 4,2).
(1)若∠ACB的平分线CD所在直线方程为
,B(3,1),求点C的坐标;
(2)若两条中线所在直线分别为
,求直线BC的方程.
【答案】
(1)C(2,4)
(2)![]()
【解析】解:(1) 设C(m,2m),则![]()
∵ CB到CD的角等于CD到CA的角[来源:学|科|网]
∴
![]()
∴ m = 2
∴ C(2,4)··········································································· 6分
![]()
∴ ![]()
∴ ![]()
∴ B(2,4),C(4,0)
∴ BC方程为
··································· 12分
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