题目内容

(本小题满分12分)

ABC中,A(– 4,2).

(1)若∠ACB的平分线CD所在直线方程为B(3,1),求点C的坐标;

(2)若两条中线所在直线分别为,求直线BC的方程.

 

【答案】

 

(1)C(2,4)

(2)

【解析】解:(1) 设Cm,2m),则

CBCD的角等于CDCA的角[来源:学|科|网]

m = 2

C(2,4)··········································································· 6分

B(2,4),C(4,0)

BC方程为··································· 12分

 

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