题目内容
已知sinα=
,cosβ=
,且α,β均为锐角,则α+β=______.
| 1 | ||
|
| 2 | ||
|
∵sinα=
,cosβ=
,且α,β均为锐角
∴cosα=
=
,sinβ=
=
∴cos(α+β)=cosαcosβ-sinαsinβ=
×
-
×
=
∴α+β=
故答案为:
| 1 | ||
|
| 2 | ||
|
∴cosα=
| 1-sin2α |
| 3 | ||
|
| 1-cos2β |
| 1 | ||
|
∴cos(α+β)=cosαcosβ-sinαsinβ=
| 3 | ||
|
| 2 | ||
|
| 1 | ||
|
| 1 | ||
|
| ||
| 2 |
∴α+β=
| π |
| 4 |
故答案为:
| π |
| 4 |
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