题目内容
已知
=(5
cosx,cosx),
=(sinx,2cosx),其中x∈[
,
],设函数f(x)=
•
+|
|2+
.
(1)求函数f(x)的值域;
(2)若f(x)=5,求x的值.
| a |
| 3 |
| b |
| π |
| 6 |
| π |
| 2 |
| a |
| b |
| b |
| 3 |
| 2 |
(1)求函数f(x)的值域;
(2)若f(x)=5,求x的值.
(1)f(x)=5
cosxsinx+2cos2x+sin2x+4cos2x+
=
sin2x+5•
+
=5sin(2x+
)+5.…(3分)
∵x∈[
,
],∴2x+
∈[
,
].
∴sin(2x+
)∈[-
,1],故f(x)的值域为[
,10].…(5分)
(2)若f(x)=5,则sin(2x+
)+5=5,即sin(2x+
)=0.
∵2x+
∈[
,
],∴2x+
=π?x=
.…(10分)
| 3 |
| 3 |
| 2 |
=
5
| ||
| 2 |
| cos2x+1 |
| 2 |
| 5 |
| 2 |
| π |
| 6 |
∵x∈[
| π |
| 6 |
| π |
| 2 |
| π |
| 6 |
| π |
| 2 |
| 7π |
| 6 |
∴sin(2x+
| π |
| 6 |
| 1 |
| 2 |
| 5 |
| 2 |
(2)若f(x)=5,则sin(2x+
| π |
| 6 |
| π |
| 6 |
∵2x+
| π |
| 6 |
| π |
| 2 |
| 7π |
| 6 |
| π |
| 6 |
| 5π |
| 12 |
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