题目内容
| 1-cos210° |
| 1+cos210° |
原式=
+
=
+
=
+
=
.
故答案为:
| 1-cos(180°+30°) |
| 1+cos(180°+30°) |
=
| 1+cos30° |
| 1-cos30° |
| ||
| 2 |
| ||
| 2 |
| ||||
| 2 |
故答案为:
| ||||
| 2 |
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相关题目
将下列三角函数转化为锐角三角函数,并填在题中横线上:
|
(1)cos210° =________; |
(2)sin263°42′ =________; |
|
(3) |
(4) |
|
(5) |
(6)cos( -104°26′)=________; |
|
(7)tan632°24′ =________; |
(8) |