题目内容

(本题满分15分)

已知,

(1)当时,

1解关于的不等式

2当时,不等式恒成立,求的取值范围;

(2)证明不等式

  (1) 1当时,,(2分)

       对应方程的两根为(3分)

        时,;(4分)

        时,.(5分)

       2当时,

           ,(6分), ,(8分 ) ,当时,,(9分 )

     .(10分)

    (2).

       (12分)

              (13分)

              (14分)

              .(15分)

(注:也可以用比差法证明.作差1分,因式分解2分,定符号下结论2分.)

      

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