题目内容
在数列A.
B.
C.
D.![]()
A由题知an+1-an=ln(1+
),
故(a2-a1)+(a3-a2)+(a4-a3)+…+(an-an-1)
=ln
×
×
×…×
=lnn,
即an-a1=lnn.∴an=a1+lnn=2+lnn.
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题目内容
在数列A.
B.
C.
D.![]()
A由题知an+1-an=ln(1+
),
故(a2-a1)+(a3-a2)+(a4-a3)+…+(an-an-1)
=ln
×
×
×…×
=lnn,
即an-a1=lnn.∴an=a1+lnn=2+lnn.