Question

计算：|-0.01|-

1

2

-(-

5

7

)0+3log32+(lg2)2+lg2•lg5+lg5．

Answer 1

原式=(

1

100

)-

1

2

-1+2+lg2(lg2+lg5)+lg5
=(100-1)-

1

2

-1+2+lg2(lg2+lg5)+lg5
=100

1

2

-1+2+lg2(lg2+lg5)+lg5
=10-1+2+lg2+lg5
=12