题目内容
已知
,
是非零向量,且
,
夹角为
,则向量
=
+
的模为______.
| a |
| b |
| a |
| b |
| π |
| 3 |
| p |
| ||
丨
|
| ||
丨
|
∵|
|=
=1=|
|,
?
=|
| |
|cos
=
|
| |
|
∴
2=|(
+
)2=1+1+2?
?
=2+2×
=3,
∴|
|=
.
故答案为
.
| ||
|
|
|
| ||
|
|
| ||
|
|
| a |
| b |
| a |
| b |
| π |
| 3 |
| 1 |
| 2 |
| a |
| b |
∴
| p |
| ||
|
|
| ||
|
|
| ||
|
|
| ||
|
|
| 1 |
| 2 |
∴|
| p |
| 3 |
故答案为
| 3 |
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,
是非零向量,满足
=λ
,
=λ
(λ∈R),则λ=( )
| a |
| b |
| a |
| b |
| b |
| a |
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