题目内容
logab2logb2a=
1
1
.分析:logab2logb2a═
×
,由此能求出其结果.
| lgb2 |
| lga |
| lga |
| lgb2 |
解答:解:logab2logb2a
=
×
=1.
故答案为:1.
=
| lgb2 |
| lga |
| lga |
| lgb2 |
=1.
故答案为:1.
点评:本题考查对数的运算性质,解题时要认真审题,注意对数运算法则的灵活运用.
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