题目内容
用二次项定理证明32n+2-8n-9能被64整除(n∈N).
证明:32n+2-8n-9=9n+1-8n-9=(8+1)n+1-8n-9
=C
8n+1+C
8n+…+C
82+C
8+C
-8n-9
=64(C
8n-1+C
8n-2+…+C
)+8(n+1)+1-8n-9
=M×64(记M=C
8n-1+C
8n-2+…+C
).
∵ M为整数,∴ 64M能被64整除.
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题目内容
用二次项定理证明32n+2-8n-9能被64整除(n∈N).
证明:32n+2-8n-9=9n+1-8n-9=(8+1)n+1-8n-9
=C
8n+1+C
8n+…+C
82+C
8+C
-8n-9
=64(C
8n-1+C
8n-2+…+C
)+8(n+1)+1-8n-9
=M×64(记M=C
8n-1+C
8n-2+…+C
).
∵ M为整数,∴ 64M能被64整除.