题目内容


用二次项定理证明32n+2-8n-9能被64整除(n∈N).


证明:32n+2-8n-9=9n+1-8n-9=(8+1)n+1-8n-9

=C8n+1+C8n+…+C82+C8+C-8n-9

=64(C8n-1+C8n-2+…+C)+8(n+1)+1-8n-9

=M×64(记M=C8n-1+C8n-2+…+C).

∵ M为整数,∴ 64M能被64整除.


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