题目内容

求下列函数的导数:

(1)y=x5-3x3-5x2+6;

(2)y=

(3)y=

(4)y=(2x2+3)(3x-2);

(5)y=sin2x.

答案:
解析:

  解析:(1)=(x5-3x3-5x2+6=(x5-(3x3-(5x2=5x4-9x2-10x

  (2)=(+(=(2x-2+(3x-3

  =-4x-3-9x-4

  (3)

  =

  (4)方法一:=(2x2+3(3x-2)+(2x2+3)·(3x-2

  =4x(3x-2)+(2x2+3)·3

  =18x2-8x+9

  方法二:∵y=(2x2+3)·(3x-2)=6x3-4x2+9x-6

  ∴=18x2-8x+9

  (5)∵y=sin2x=2sinxcosx

  ∴=2(sinxcosx+2sinx·(cosx

  =2cos2x-2sin2x

  =2cos2x


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