Question

把曲线ycosx+2y-1=0先沿x轴向右平移个单位，再沿y轴向下平移1个单位，得到的曲线方程是（    ）

A.(1-y)sinx+2y-3=0                         B.(y-1)sinx+2y-1=0

C.(y+1)sinx+2y+1=0                        D.-(y+1)sinx+2y+1=0

Answer 1

解析：根据平移变换规律，将ycosx+2y-1=0沿x轴向右平移个单位，得ycos(x-)+2y-1=0,即ysinx+2y-1=0①,再将①沿y向下平移1个单位，得(y+1)sinx+2(y+1)-1=0,即（y+1）sinx+2y+1=0.

答案:C