Question

若log_x(2x²+1)＜log_x(3x)＜0成立，则x的取值范围是

A.(0，)                                                       B.(0，)

C.(，1)                                                       D.(，)

Answer 1

D

解析:

对于log_x(3x)＜0，若x＞1,则3x＜1,矛盾，故0＜x＜1.

又2x²+1＞3x＞1,∴＜x＜.