题目内容
(log43+log83)(log32+log92).
解法一:原式=log43·log32+log83·log32+log43·log92+log83·log92
=log
3·log32+log
3·log32+log
3·log
2+log233·log
2
=
log23·log32+
log23·log32+
log23·
log32+
log23·
log32=
+
+
+
=
.
解法二:原式=(log223+log233)·(log32+log322)
=(
log23+
log23)(log32+
log32)
=
log23×
log32=
.
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