题目内容
若命题“?x∈R,x2+(a-1)x+1<0”是假命题,则实数a的取值范围是( )
| A.[-1,3] | B.[1,4] | C.(1,4) | D.(-∞,1]∪[3,+∞) |
若命题“?x∈R,x2+(a-1)x+1<0”是假命题,
则命题“?x∈R,x2+(a-1)x+1≥0”是假命题,
则方程x2+(a-1)x+1=0中
△=(a-1)2-4≤0,
解得-1≤a≤3
故选A
则命题“?x∈R,x2+(a-1)x+1≥0”是假命题,
则方程x2+(a-1)x+1=0中
△=(a-1)2-4≤0,
解得-1≤a≤3
故选A
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