Question

已知不等式≥0(a＜b)的解集是{x|-1≤x＜2或x≥3}，则不等式≤0的解集为__________________.

Answer 1

解析：显然由条件可知c=2,a=-1,b=3,从而有解集为{x|x＜-1或2＜x≤3}.

答案：{x|x＜-1或2＜x≤3}